Answer: Normal Force of the ground pushing the athlete up.
Explanation: I did this on Khan Academy and got the answer right.
Answer:
u=10m/s
a=-10m/s²
v=0m/s
s=v²-u²/2a
s=0-100/-10
s=-100/-10
s=10m
t=v-u/a
t=0-10/-10
t=-10/-10
t=1second
2.815 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Time taken with the acceleration is 94.25 seconds
Time = Distance / Speed
Difference in time = 97.065-94.25 = 2.815 seconds