Question

The electric field at a distance of 5cm from the center of a charged dome is 3 * 10 ^ 4 * N * C ^ - 1 . Calculate the charge (Q) on the dome.

Answer 1

Explanation:

Q is the charge, 9×10^9×3×10^4 is the magnitude ,d = 5 cm therefore q=3×10^4÷5^2=2.7×10^14÷25=1.08×10^13 c