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enyata [817]
3 years ago
12

Max observes a spaceship traveling toward him at 0.75c. He measures its length and finds that the spaceship is 250 m long. The s

hip brakes hard and skids to a stop on a nearby airstrip. Max remeasures the spaceship. What length does he find
Physics
1 answer:
sladkih [1.3K]3 years ago
6 0

Answer:

380m

Explanation:

We have the speed of the spaceship v = 0.75c

Max measures contracted length L of the spaceship as it travels

We have been given L = 250m

As this ship stops he is going to get exact length of the ship = Lol

We solve using this formula

L = Lo√ 1-v²/c²

From the formula above we make Lo subject of the formula

When we input values

Lo = 250/√1-(0.75c/c)²

= 250/√1-(0.75)²

= 250/√0.4375

= 250/0.6614

= 377.98

This is approximately 380

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Explanation:

Samantha walks along a horizontal path in the direction shown the curved path is a semi circle with a radius of 2 m while the horizontal part is for me what is the magnitude of displacement

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a semi circle with a radius of 2 m

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=4+(2*2)

=8 m

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What can electromagnetic waves travel through?
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Why is it important foe scientists to know how many valence electrons a given element has
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The density of a substance equals its mass divided by its volume. Talia listed the density of some common materials at 20 °C.
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Read 2 more answers
Experimenting with free fall, Mariana observes that her baseball takes 1.5 s to travel the last 30m before hitting the ground. F
Art [367]

Answer:

37.8 m

Explanation:

At point 0, the ball is at height y₀.

At point 1, the ball is at height 30 m.

At point 2, the ball is at height 0 m.

Given:

y₁ = 30 m

y₂ = 0 m

v₀ = 0 m/s

a = -10 m/s²

t₂ − t₁ = 1.5 s

Find: y₀

Use constant acceleration equation.

y = y₀ + v₀ t + ½ at²

Evaluate at point 1.

y₁ = y₀ + v₀ t₁ + ½ at₁²

30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²

30 = y₀ − 5t₁²

Evaluate at point 2.

y₂ = y₀ + v₀ t₂ + ½ at₂²

0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²

0 = y₀ − 5t₂²

y₀ = 5t₂²

Substitute:

y₀ = 5 (1.5 + t₁)²

y₀ = 5 (2.25 + 3t₁ + t₁²)

y₀ = 11.25 + 15t₁ + 5t₁²

30 = 11.25 + 15t₁ + 5t₁² − 5t₁²

30 = 11.25 + 15t₁

t₁ = 1.25

30 = y₀ − 5t₁²

30 = y₀ − 5(1.25)²

y₀ ≈ 37.8

4 0
3 years ago
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