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Greeley [361]
3 years ago
8

3 kg

Physics
1 answer:
Jet001 [13]3 years ago
3 0

Answer:

The total normal force acting on the system is approximately 58.8 N

Explanation:

The masses arranged in the stack are;

3 kg, 2 kg, and 1 kg

The mass of the stack system, m = 3 kg + 2 kg + 1 kg = 6 kg

Weight = The force of gravity on an object = m·g

Where;

m = The mass of the object

g = The acceleration due to gravity ≈ 9.8 m/s²

∴ The weight of the stack system, W ≈ 6 kg × 9.8 m/s² ≈ 58.8 N

The direction of the weight force = Perpendicular to the surface (acting downwards)

From Newton's third law of motion, the normal force acts perpendicular to the plane and it is equal in magnitude to the force acting perpendicular to the plane

∴ The magnitude of the total normal force acting on the system = The magnitude of the weight of the system ≈ 58.8 N

The (magnitude of the) total normal force acting on the system ≈ 58.8 N

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A student hangs a weight on a newtonmeter. The energy currently stored in the spring in the newton meter is 0.045N. The student
castortr0y [4]

Answer:

5x10^-3

Explanation:

Hooke's Law states that the force needed to compress or extend a spring is directly proportional to the distance you stretch it.

Hooke's Law can be represented as

<h3> F = kx, </h3>

<em>where F is the force </em>

<em>            k is the spring constant</em>

<em>            x is the extension of the material </em>

<em />

Plug values in the equation

Step 1 find the original extension

0.045 = (400)x

x = 1.125x 10^-4 m d

Step 2 find the new extension

0.045+2 = 400(x)

2.045 = 400x

x = 5.1125x10^-3

Step 3 subtract the new extension with original

Total extension of the spring =  5.1125x10^-3 - 1.125x 10^-4 m = 5x10^-3

8 0
3 years ago
While moving a box 10.0 m across the floor, Sam pushes with a force of 150 N to the right. The force friction acting on the box
svet-max [94.6K]

Answer:

Explanation:required formula is

W 1=F*S

W1=work done by Sam =?

F=force applied by sam=150N

S=displacement =10m

again

W2=F*S

W2=work done by friction =?

S=displacement =10m

F=friction =25N

W=W1-W2=net work done

please feel free to ask if you have any questions

4 0
3 years ago
Hi i need help. thNKS
Ede4ka [16]

Answer:

8

Explanation:

Groups go down, periods go across :)

3 0
3 years ago
If rho(x,y) is the density of a wire (mass per unit length), then
lidiya [134]

Answer:

See description

Explanation:

With the given information we have:

x(t) = 1 + cos(t)\\ y(t)=sin(t)\\ \rho(x,y) = 3x

the interval is [0,\pi ]

now the mass m has the given expression:

m = \int \rho(x,y) dS

we will use the formula for a line integral and let:

dS=\sqrt{x'(t)^2 + y'(t)^2}=\sqrt{cos(t)^2 + sin(t)^2}dt=dt

therefore we have:

m=\int \rho(x,y)dS=\int\limits^\pi_0 {3*x}dS=\int\limits^\pi _0{3*(1+cos(t))dS\\=\int\limits^\pi _0{3*(1+cos(t))dt

we solve the integral:

m=3*\int\limits^\pi _0{(1+cos(t))dt= 3*(t+sin(t))\limits^\pi _0=3*\pi=9.42

7 0
3 years ago
Which atom is invloved in giving your heart energy to beat ?
Juli2301 [7.4K]

Answer:

Oxygen

Explanation:

5 0
3 years ago
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