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Greeley [361]
3 years ago
8

3 kg

Physics
1 answer:
Jet001 [13]3 years ago
3 0

Answer:

The total normal force acting on the system is approximately 58.8 N

Explanation:

The masses arranged in the stack are;

3 kg, 2 kg, and 1 kg

The mass of the stack system, m = 3 kg + 2 kg + 1 kg = 6 kg

Weight = The force of gravity on an object = m·g

Where;

m = The mass of the object

g = The acceleration due to gravity ≈ 9.8 m/s²

∴ The weight of the stack system, W ≈ 6 kg × 9.8 m/s² ≈ 58.8 N

The direction of the weight force = Perpendicular to the surface (acting downwards)

From Newton's third law of motion, the normal force acts perpendicular to the plane and it is equal in magnitude to the force acting perpendicular to the plane

∴ The magnitude of the total normal force acting on the system = The magnitude of the weight of the system ≈ 58.8 N

The (magnitude of the) total normal force acting on the system ≈ 58.8 N

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Explanation:

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In the case of having two values, two electrons change. In the case of three allowed values, one electron fits for each value, so in a given orbital there can be 3 electrons.

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4 years ago
You hear a sound in the distance. Suddenly the sound gets deeper, decreasing in pitch. Which can you assume about the sound wave
oksian1 [2.3K]

Answer:

A. The wavelengths of the new sound waves are longer

Explanation:

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8 0
4 years ago
What the kinetic energy quantities in calculation pls help me​
Rashid [163]

Answer:

KE = 0.5 * m * v², where: m - mass, v - velocity.

Explanation:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s 2.

3 0
3 years ago
A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear
Talja [164]

Answer:

70.07 Hz

Explanation:

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76 = f_s\times\frac {(343-vs)}{343}

f_s=\frac {343\times 76}{343-v_s}

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65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}

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f_s=70.07 Hz

4 0
3 years ago
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