Answer:
ΔG = - 31.7kJ/mol
Explanation:
It is possible to find ΔG of a reaction at certain temperature knowing Kc following the equation:
ΔG = ΔG° + RT ln Q
ΔG° = -RT lnKc
ΔG = -RT lnKc + RT ln Q (1)
<em>Where R is gas constant (8.314J/molK), T absolute temperature (350°C + 273.15 = 623.15K) and Q reaction quotient</em>
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For the reaction,
3H₂(g) + N₂(g) ⇄ 2NH₃(g)
Q = [NH₃]² / [H₂]³[N₂]
Where the concentrations of each chemical are:
[NH₃] = 1.0mol / 2.5L = 0.4M
[H₂] = 5.0mol / 2.5L = 2M
[N₂] = 2.5mol / 2.5L = 1M}
Q = [0.4M]² / [2M]³[1M]
Q = 0.02
And replacing in (1):
ΔG = -RT lnKc + RT ln Q
ΔG = -8.314J/molK*623.15K ln 9 + 8.314J/molK*623.15K ln 0.02
ΔG = - 31651J/mol
<h3>ΔG = - 31.7kJ/mol</h3>
I’m so sorry don’t know just need the points asap
Answer:
0.525 M CuSO
Explanation:
Molarity (M) is the units mol/L. Let's figure out how many moles of CuSO we have:
35 mL = 35/1000 L = 0.035 L
0.035 L * 1.50 mol/L = 0.0525 mol CuSO
Our new volume is 100 mL, so let's first convert this to L:
100 mL = 100/1000 L = 0.100 L
To find the new molarity, divide the number of moles (0.0525 moles) by the number of liters (0.100 L):
0.0525 mol / 0.100 L = 0.525 M CuSO
Hope this helps!
Answer:
depends
Explanation:
if there was a picture i could help you
Answer:
A
Explanation:
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