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guajiro [1.7K]
2 years ago
6

What type of slab and beam used in construction of space neddle​

Engineering
1 answer:
Sav [38]2 years ago
5 0

jrjrkeekkekekkwkkakkllalllalallalllalalaallalalaalalalalalallallallllallalalallaaallalallllllallllllllalaalalalaaaaalalaaaaaaalgjgiejxpwunfifjruritiririirieoeowowowowowowowowooeowowowoeeoeowowowowowowowoowowwowowowoozoeisiaokseekxidjdkdjfidjfjdjfjfjrifjrifjdirjdjrjfjrjfjrjfjrfuejwwuxmaneanfjkaosndjxieneamalhaqzeeshanvhorahfuensiwjakaksjdhfhfnfhfndjxnxmakaalalalwlwlwwow

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Which of the following is a advantage of a chain and sprocket over a pulley and belt system?
Tatiana [17]

Answer:

A) Cost

Explanation:

Chain drives have low maintenance cost.

3 0
2 years ago
Free ideas free points. You will be reported for answering "no" or I don't know
KengaRu [80]

Answer:

Here are some cool ideas that you could do

-Zero fuel aircraft

-Advanced Space Propulsion Technologies

-Smart Automation and Blockchain

These are some things I've been working on for a few years lol, maybe you will have more luck

5 0
3 years ago
Wet steam at 15 bar is throttled adiabatically in a steady-flow process to 2 bar. The resulting stream has a temperature of 130°
cricket20 [7]

Answer:

\Delta s = 0.8708\,\frac{kJ}{kg\cdot K}

Explanation:

The adiabatic throttling process is modelled after the First Law of Thermodynamics:

m\cdot (h_{in} - h_{out}) = 0

h_{in} = h_{out}

Properties of water at inlet and outlet are obtained from steam tables:

State 1 - Inlet (Liquid-Vapor Mixture)

P = 1500\,kPa

T = 198.29\,^{\textdegree}C

h = 2726.9\,\frac{kJ}{kg}

s = 6.3068\,\frac{kJ}{kg\cdot K}

x = 0.967

State 2 - Outlet (Superheated Vapor)

P = 200\,kPa

T = 130\,^{\textdegree}C

h = 2726.9\,\frac{kJ}{kg}

s = 7.1776\,\frac{kJ}{kg\cdot K}

The change of entropy of the steam is derived of the Second Law of Thermodynamics:

\Delta s = 7.1776\,\frac{kJ}{kg\cdot K} - 6.3068\, \frac{kJ}{kg\cdot K}

\Delta s = 0.8708\,\frac{kJ}{kg\cdot K}

6 0
3 years ago
A 12-ft circular steel rod with a diameter of 1.5-in is in tension due to a pulling force of 70-lb. Calculate the stress in the
padilas [110]

Answer:

The stress in the rod is 39.11 psi.

Explanation:

The stress due to a pulling force is obtained dividing the pulling force by the the area of the cross section of the rod. The respective area for a cylinder is:

A=\pi*D^2/4

Replacing the diameter the area results:

A= 17.76 in^2

Therefore the the stress results:

σ = 70/17.76 lb/in^2 = 39.11 lb/in^2= 39.11 psi

5 0
2 years ago
Which of the following describes all illustrations created by freehand?
Klio2033 [76]

extension lines,sketches,leader lines,dimensions describes all illustrations created by freehand.

5 0
3 years ago
Read 2 more answers
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