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4 years ago

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Physics

1 answer:

sergiy2304 [10]4 years ago

5 0

Answer:

The two neighboring planets with the greatest distance between them is Neptune and Uranus. This happens when they are at the opposite sides of the Sun at approximately. They are 4500 million miles away from each other.

If by adjacent you mean next to each other, in terms of the order of planets in our Solar System, then the closest would be Earth and Venus; which are separated by about 38,000,000 kilometres when in opposition.

I am not sure about the general patterns..

Venus has the longest day of any planet in our solar system. It completes one rotation every 243 Earth days.

A year on Neptune is the longest of any planet, lasting the equivalent of 164.8 years (or 60,182 Earth days). It is obvious because it is also the farthest with the longest orbit.

Outer planets are less dense than the inner planets because they posses a big volume but contains not much mass. Try to imagine 2 rocks, one is big, but is hollow or have a lot of holes; and the other is small, but solid with no holes.

Happy learning!!

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My name is Ann [436]

The crate is moving at constant velocity when the forces acting on it are

balanced.

The value of the force F required to pull the crate with constant velocity is; $\underline{F = \sqrt{2} \cdot \mu \cdot m\cdot g}$

Reasons:

Mass of the crate = m

Cross section of through = Right angled

Orientation (inclination) of the through to horizontal = 45°

Coefficient of kinetic friction = μ

Required:

The value of the required to pull the crate along the through at constant

velocity.

Solution:

When the through is moving at constant velocity, we have;

Friction force acting on crate = Force pulling the crate

Friction force = Normal reaction × Coefficient of kinetic friction

Normal reaction on an inclined plane = $\mathbf{F_N}$

Each side of the through gives a normal reaction.

The vertical component of the normal reaction on each side of the through

is therefore;

$F_N$ ·j = $\mathbf{F_N}$ × sin(θ)

The sum of the vertical component = $F_N$ ·j + $F_N$ ·j = 2· $F_N$ ·j = 2· $F_N$ ×sin(θ)

The sum of the vertical component of the normal reactions = The weight of the crate

Therefore;

2· $F_N$ ×sin(θ) = m·g

θ = 45°

Therefore;

2· $F_N$ ×sin(45°) = m·g

$\displaystyle sin(45^{\circ}) = \mathbf{\frac{\sqrt{2} }{2}}$

Therefore;

$\displaystyle 2 \cdot F_N \cdot sin(45^{\circ}) = 2 \cdot F_N \times \frac{\sqrt{2} }{2} = \sqrt{2} \cdot F_N$

$\displaystyle F_N = \mathbf{ \frac{m \cdot g}{\sqrt{2} }}$

Which gives;

$\displaystyle Force \ required, \ F = Sum \of \ friction \ forces \ = 2 \times F_N \times \mu = \mathbf{ 2 \times \frac{m \cdot g}{\sqrt{2} } \times \mu}$

$\displaystyle Force \ required, \ F = 2 \times \frac{m \cdot g}{\sqrt{2} } \times \mu = \mathbf{ \sqrt{2} \cdot \mu \cdot m \cdot g}$

Force required to pull the crate at constant velocity, F = √2·μ·m·g

Learn more about force of friction here:

brainly.com/question/6561298

8 0

2 years ago

Read 2 more answers

1. Take the speed at which the body moves as 10 m/s 2. Calculate the distance travelled by the body every second 3. Take the tim

exis [7]

Answer:

a)this graph is also a line b) in both cases we have a uniform movement

Explanation:

In this exercise we have a uniform movement

v = d / t

d = v t

in the table we give some values to make the graph

t (s) d (m)

1 10

2 20

3 30

In the attached we can see the graph that is a straight line

we have another vehicle at v = 50 me / S

t (s) d (m)

1 50

2 100

3 150

this graph is also a line

b) in both cases we have a uniform movement

3 0

4 years ago

When light falls on objects, it interacts with them in different ways as shown in the images. What type of interaction is seen i

ra1l [238]

Total absorption of the light takes place in every image. There is no light left to proceed to our eyes, and that's why we can't see any of the images.

The absorption is so complete in each and every case, we can't even see enough to know how MANY images there are.

4 0

3 years ago

Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =

Crank

Answer:

Fnet = 12 N

Explanation:

Force on a point charge due to another point charge = kq1q2 / d^2

Force on +32uC = due to + 20uC + due to -60uC

where uC = 1 x 10^-6 C and k = 9 x 10^9 N m^2 / C^2

Net Force =

$= \frac{1}{4\pi \epsilon _0} [\frac{32 \times 10^-^6 \times60\times10^-^6}{(60/100)^2}-\frac{32 \times 10^-^6 \times20\times10^-^6}{ (40/100)^2} ]$

$F_{net}=9 \times10^9\times 10^-^1^2[\frac{32\times60\times10^4}{60\times60} -\frac{32\times20\times10^4}{40\times40} ]$

$=90[32(\frac{80-60}{60\times 80} )]\\\\=90\times32\times0.004167\\\\=12N$

Fnet = 12 N

8 0

4 years ago

Which term describes the wave phenomenon in the image

aleksley [76]

Answer: (Next time put the Image but I know what u talkin bout)

wave changes its path from its initial direction so this phenomenon is known as Refraction of wave

Explanation:

When wave travels from one medium to other medium the due to change in the speed of the wave propagation it deviates from its initial path.

The deviation of the wave from its initial path is known as refraction of wave

Here we can see that wave incident on medium 1 with some angle with the boundary

Then it enters into other medium and then travels in other direction

So here wave changes its path from its initial direction so this phenomenon is known as Refraction of wave

4 0

3 years ago