All categories

3 years ago

Which element comes from the greek word zinke?

Chemistry

2 answers:

Novay_Z [31]3 years ago

8 0

Answer:

Zinc

The element was probably named by the alchemist Paracelsus after the German word Zinke (prong, tooth).

Explanation:

Neporo4naja [7]3 years ago

5 0

Answer: Zinc

Explanation: The element was probably named by the alchemist Paracelsus after the German word Zinke (prong, tooth).

You might be interested in

Can you describe the situations when Greek prefixes are used?

Black_prince [1.1K]

Answer:

Here's what I get

Explanation:

At the introductory level of chemistry, I can think of only two situations when you use Greek prefixes.

They indicate the number of atoms or groups in a molecule when you are naming a compound.

1. Binary covalent compounds

For example, P₂S₅ is diphosphorus pentasulfide.

2. Hydrates

For example, Na₂SO₄·10H₂O is sodium sulfate decahydrate.

7 0

3 years ago

Calculate the number of moles of sodium carbonate originally present, if 6.0 ml of 0.100 M HCl were used to titrate the mixture

valina [46]

Answer:

0.0006 mole

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For HCl :

Molarity = 0.100 M

Volume = 6.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.0×10⁻³ L

Thus, moles of potassium iodide :

$Moles=0.100 \times {6.0\times 10^{-3}}\ moles$

Moles of HCl = 0.0006 moles

From the reaction shown below:-

$HCl+Na_2CO_3\rightarrow NaHCO_3+NaCl$

1 mole of HCl reacts with 1 mole of sodium carbonate.

So,

0.0006 mole of HCl reacts with 0.0006 mole of sodium carbonate.

<u>Moles of sodium carbonate = 0.0006 moles</u>

5 0

3 years ago

What are the concentrations of h3o+ and oh− in tomatoes that have a ph of 4.10?

IRINA_888 [86]

Answer : The concentration of $H_3O^+$ and $OH^-$ are $7.94\times 10^{-5}$ and $1.258\times 10^{-10}$ respectively.

Solution : Given,

pH = 4.10

pH : pH is defined as the negative logarithm of hydronium ion concentration.

Formula used : $pH=-log[H_3O^+]$

First we have to calculate the hydronium ion concentration by using pH formula.

$4.10=-log[H_3O^+]$

$[H_3O^+]=antilog(-4.10)$

$[H_3O^+]=7.94\times 10^{-5}$

Now we have to calculate the pOH.

As we know, $pH+pOH=14$

$4.10+pOH=14$

$pOH=9.9$

Now we have to calculate the hydroxide ion concentration.

$pOH=-log[OH^-]$

$9.9=-log[OH^-]$

$[OH^-]=antilog(-9.9)$

$[OH^-]=1.258\times 10^{-10}$

Therefore, the concentration of $H_3O^+$ and $OH^-$ are $7.94\times 10^{-5}$ and $1.258\times 10^{-10}$ respectively.

5 0

3 years ago

What were the main causes of conflict between the nawab of bengal and the east india company

stich3 [128]

1 The British opposed the succession of Sirajuddaulah

2 The British misued the trade concessions

3 The British attacaked the French settlement of
Chandranagar in Bengal

<span>4 The Incident of Black hole had occured</span>

5 0

4 years ago

Like Earth, the moon

dedylja [7]

Um all? i’m confused

5 0

3 years ago