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melamori03 [73]
3 years ago
9

If a 130-kg car is traveling at a velocity of 23 m/s, what is the kinetic energy of the car?​

Chemistry
2 answers:
Iteru [2.4K]3 years ago
5 0

Answer:

1/2*(23 ^2)*130=34385

AnnZ [28]3 years ago
3 0
KE = 1/2 * m * v^2
KE = 1/2 * 130 * 23^2
KE = 34385J
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Explanation:

According to the psychrometric chart at dry bulb temperature of 21^{o}C and RH 70%, the absolute humidity = 0.011 kg/kg dry air

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                     = (2.83 \times 10^{-3} + 4.56 \times 10^{-3} H) T K

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Hence, the specific enthalpy of the air is 21.126 kJ/kg dry air.

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putting the values in the rearranged equation:

V = \frac{2.49 X10^{-26}   X 0.08201 X 273}{1}

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Answer:

c

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