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2 years ago

6

Sam needs a web designer. Designer A is offering her services for an initial $460 in addition to $100 per hour. Designer B is of

fering her services for an initial $730 in addition to $55 per hour. When will the two designers charge the same amount of money?

1 answer:

arsen [322]2 years ago

7 0

The designers will Charge the same amount at $700. 500+100*2=700 and 600+50*2=700

You might be interested in

Which list of ordered pairs is NOT a function? Mark only one oval. {(1, 1), (2, 3), (3, 4), (4,5)} ){(1, 1), (2, 2), (3, 3), (4,

Mrac [35]

Answer:

{(1, 1), (1, 3), (2, 3), (3,4)} is not a function.

Step-by-step explanation:

The lists are:

a) {(1, 1), (2, 3), (3, 4), (4,5)}

b) {(1, 1), (2, 2), (3, 3), (4,4)}

c) {(1, 1), (3, 1), (4,2), (5, 3) }

d) {(1, 1), (1, 3), (2, 3), (3,4)}

Firs, let's define what is a function.

A function is a relationship that maps elements from a set (the domain, is the set of the inputs) into elements of another set (the range, the set of the outputs) such that each element of the domain can be mapped into only one element of the range.

Then the list where we have the same input mapped into two different outputs, will not be a function.

Where in a ordered pair (x, y)

x is the input, and y is the output.

In this case, the list that is not a function is:

d) {(1, 1), (1, 3), (2, 3), (3,4)}

because we have the input x = 1, mapped into two different outputs.

5 0

2 years ago

PLEASE HELP!!!!!!!!!!

erik [133]

Answer: D

Step-by-step explanation:

7 0

2 years ago

For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.

andriy [413]

Answer:

If $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

The signal of $\bigtriangleup$ determines how many real roots an equation has:

$\bigtriangleup > 0$ : Two real and different solutions

$\bigtriangleup = 0$ : One real solution

$\bigtriangleup < 0$ : No real solutions

In this problem, we have the following second order polynomial:

$(k+1)x^{2} + 4kx + 2 = 0$ .

This means that $a = k+1; b = 4k; c = 2$

It has one solution if

$\bigtriangleup = 0$

$b^{2} - 4ac = 0$

$16k^{2} -8(k+1) = 0$

$16k^{2} - 8k - 8 = 0$

We can simplify by 8

$2k^{2} - k - 1 = 0$

The solution is:

$k = 1$ or $k = -\frac{1}{2}$

So, if $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

4 0

3 years ago

Okay, help me out here!!

luda_lava [24]

Answer:

65.8

Step-by-step explanation:

(2.6*4.7)/2=6.11

11*4.7=51.7

(4.7(17-(2.6+11)))/2=7.99

6.11+51.7+7.99=65.8

3 0

3 years ago

Please help.................

evablogger [386]

It usually works well to do what the instructions tell you. Multiply each diameter by 3.14.

a) 3.14×6 cm = 18.84 cm

b) [can't read the picture]

d) 3.14×9 in = 28.26 in

e) 3.14×11 mm = 34.54 mm

7 0

3 years ago