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melamori03 [73]
3 years ago
14

A. A man of 100 kg mass is standing on the surface of the earth of mass 6 × 1024 kg and

Physics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

m1=100kg

m2=6×10^24kg

r=6400km

G=6.6×10^-11

F=?

as we know that

F=G m1.m2/r²

F=6.6×10^-11×100×6×10^24/(6400)²

F=6.6×10^-11×6×10^26/4.096×10^7

F=6.6×10^-11×1.465×10^19

F=9.67×10^8N

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Part (a):
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Part (b):
First, we will get the total distance traveled by the ball as follows:
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v^2 = u^2 + 2as
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v = 159.99985 m/sec
Therefore, the velocity of the ball would be 159.99985 m/sec when it hits the ground.
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