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3 years ago

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It is desired to produce a continuous and oriented carbon fiber-reinforced epoxy having a modulus of elasticity of at least 83 G

Pa in the direction of fiber alignment. The modulus of elasticity of the graphite fiber is 260 GPa, and the modulus of elasticity of the epoxy is 2.4 GPa. What is the minimum volume fraction of fibers required to meet this requirement. (this is a Chapter 16 problem) Answer: the minimum fiber volume fraction is:__________

1 answer:

lukranit [14]3 years ago

3 0

Answer:

0.3129

Explanation:

Calculate The minimum fiber volume fraction using the relation below

E = x * E1 + ( 1 - x ) E2 ------ ( 1 )

given that :

E = 83 GPa , x = ?

E1 = 260 GPa , E2 = 2.4 GPA

Insert values back into equation 1

Then ; 80.6 = 257.6 x

∴ x ( volume fraction ) = 80.6 / 257.6 = 0.3129

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Answer:

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Explanation:

From the question we are told that:

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Generally the equation for Reactive Power is mathematically given by

Q=P(tan \theta_2-tan \theta_1)

Since

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$cos \theta_1 =0.77$

$\theta_1=cos^{-1}0.77$

$\theta_1=39.65 \textdegree$

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$\theta_2=25.84 \textdegree$

Therefore

$Q=P(tan 25.84 \textdegree-tan 39.65 \textdegree)$

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3 years ago

A closed, rigid tank is filled with a gas modeled as an ideal gas, initially at 27°C and a gage pressure of 300 kPa. If the gas

ch4aika [34]

Answer:

gauge pressure is 133 kPa

Explanation:

given data

initial temperature T1 = 27°C = 300 K

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to find out

final pressure

solution

we know that gauge pressure is = absolute pressure - atmospheric pressure so

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so gauge pressure = absolute pressure - atmospheric pressure

gauge pressure = 2.33 × $10^{5}$ - 1.0 × $10^{5}$

gauge pressure = 1.33 × $10^{5}$ Pa

so gauge pressure is 133 kPa

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Answer:

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