Answer:
The net torque is zero
Explanation:
Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.
Answer:
The difference between frictionless ramp and a regular ramp is that on a frictionless ramp the ball cannot roll it can only slide, but on a regular ramp the ball can roll without slipping.
We will use conversation of energy.
![K_A_1 + U_A_1 = K_A_2 + U_A_2\\\frac{1}{2}I\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_A](https://tex.z-dn.net/?f=K_A_1%20%2B%20U_A_1%20%3D%20K_A_2%20%2B%20U_A_2%5C%5C%5Cfrac%7B1%7D%7B2%7DI%5Comega%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%2B%200%20%3D%200%20%2B%20mgH_A)
Note that initial potential energy is zero because the ball is on the bottom, and the final kinetic energy is zero because the ball reaches its maximum vertical distance and stops.
For the ball B;
![K_B_1 + U_B_1 = K_B_2 + U_B_2](https://tex.z-dn.net/?f=K_B_1%20%2B%20U_B_1%20%3D%20K_B_2%20%2B%20U_B_2)
![\frac{1}{2}I_B\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_B](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DI_B%5Comega%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%2B%200%20%3D%200%20%2B%20mgH_B)
The initial velocities of the balls are equal. Their maximum climbing point will be proportional to their final potential energy. Since their initial kinetic energies are equal, their final potential energies must be equal as well.
Hence, both balls climb the same point.
Explanation:
Answer:
so its easier to understand for the reader
Explanation: