Why does your body feel like it’s being pushed back when a car starts back up

Earth is 149.6 million meters from the Sun and takes 365 days to make one complete revolution around the Sun. Mars is 227.9 mill

luda_lava [24]

Answer:

$\frac{a_{r,earth}}{a_{r,mars}} = 2.325$

Explanation:

The distance of Earth from the Sun is $149.6\times 10^{9}\,m$ and of Mars from the Sun is $227.9\times 10^{9}\,m$ . Let assume that both planets have circular orbits. The centripetal accelaration can be found by using the following expression:

$a_{r} = \frac{v^{2}}{R}$

Since planet has translation at constant speed, this formula is applied to compute corresponding speeds:

$v=\frac{2\pi\cdot r}{\Delta t}$

Earth:

$v_{earth} = \frac{2\pi\cdot (149.6\times 10^{9}\,m)}{(365\,days)\cdot(\frac{24\,hours}{1\,day} )\cdot(\frac{3600\,s}{1\,h} )}$

$v_{earth}=29806.079\,\frac{m}{s}$

Mars:

$v_{mars} = \frac{2\pi\cdot (227.9\times 10^{9}\,m)}{(687\,days)\cdot(\frac{24\,hours}{1\,day} )\cdot(\frac{3600\,s}{1\,h} )}$

$v_{mars}=24124.244\,\frac{m}{s}$

Now, centripetal accelarations can be found:

Earth:

$a_{r,earth} = \frac{(29806.079\,\frac{m}{s} )^{2}}{149.6\times 10^{9}\,m}$

$a_{r,earth} = 5.939\times 10^{-3}\,\frac{m}{s^{2}}$

Mars:

$a_{r,mars} = \frac{(24124.244\,\frac{m}{s} )^{2}}{227.9\times 10^{9}\,m}$

$a_{r,mars} = 2.554\times 10^{-3}\,\frac{m}{s^{2}}$

The ratio of Earth's centripetal acceleration to Mars's centripetal acceleration is:

$\frac{a_{r,earth}}{a_{r,mars}} = \frac{5.939}{2.554}$

$\frac{a_{r,earth}}{a_{r,mars}} = 2.325$

7 0

3 years ago

1. When a particle moves in a circle with constant speed, its acceleration is

omeli [17]

Answer:

Its A.

Explanation:

8 0

3 years ago

Jan first uses a Michelson interferometer with the 606 nmnm light from a krypton-86 lamp. He displaces the movable mirror away f

gogolik [260]

Answer:

a) d₁ = 247.8 μm

d₂ = 205.3 μm

b) d₂ = 20.53 x 10⁻⁵ m = 205.3 μm

Explanation:

a)

The formula for Michelson Interferometer is derived to be:

d = mλ/2

where,

d = distance moved

m = no. of fringes

λ = wavelength of light

For JAN, we have following data

d = d₁

m = 818

λ = 606 nm = 606 x 10⁻⁹ m

Therefore,

d₁ = (818)(606 x 10⁻⁹ m)/2

d₁ = 24.78 x 10⁻⁵ m = 247.8 μm

For LINDA, we have following data

d = d₂

m = 818

λ = 502 nm = 502 x 10⁻⁹ m

Therefore,

d₂ = (818)(502 x 10⁻⁹ m)/2

d₂ = 20.53 x 10⁻⁵ m = 205.3 μm

b)

The resultant displacement can be found out from the difference between both displacement. And the direction of resultant displacement will be the same as the direction of greater displacement. Therefore,

Resultant Displacement = Δd = d₁ - d₂

Δd = 247.8 μm - 205.3 μm

Δd = 42.5 μm (in the direction of JAN)

4 0

3 years ago

A 30 kg rock sits motionless on the ground. What is the normal force on the rock?

Anna [14]

Answer:30 kg

Explanation:

5 0

3 years ago

What might be done to prevent acid rain damage to objects made from metal and carbonate, such as limestone? Identify a metal obj

serg [7]

Answer: Bronze is a metal that can be damaged in acid rain. It is harsh to metals by almost burning them and may create rust. Everbrite is a clear, protective coating that will seal metal and bronze.

Explanation:

I know this is correct i have done all the research

7 0

3 years ago