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Nina [5.8K]
3 years ago
6

Why does your body feel like it’s being pushed back when a car starts back up

Physics
1 answer:
WINSTONCH [101]3 years ago
5 0

Answer:

cause of the g force pushing u back

Explanation:

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A baseball player throws a baseball with a velocity of 13 m/s north. It is caught by a second player seven seconds later. How fa
guajiro [1.7K]

Answer:

A. 91 meters north

Explanation:

Take +y to be north.

Given:

v₀ = 13 m/s

a = 0 m/s²

t = 7 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (13 m/s) (7 s) + ½ (0 m/s²) (7 s)²

Δy = 91 m

The displacement is 91 m north.

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3 years ago
If the same types of fossils are found in two separate rock layers, it's likely that the two rock layers ____. A-formed at diffe
zmey [24]
<span>B-are part of one continuous deposit.</span>
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3 years ago
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If the period of a wave is 0.05 s, then what is its frequency?
yKpoI14uk [10]
Frequency = 1/time period = 1/0.05 = 20s^-1. 
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3 years ago
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Why do we need gametes?
andrew11 [14]

Answer:

Gametes are the cells used during sexual reproduction to produce a new individual organism.

Explanation:

The male gamete or sperm, is a smaller, mobile cell that meets up with the much larger and less mobile female gamete, egg or ova.

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A closed cylinder with a 0.15-m radius ends is in a uniform electric field of 300 n/c, perpendicular to the ends. the total flux
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The total flux through the cylinder is zero.


In fact, the electric flux through a surface (for a uniform electric field) is given by:

\Phi = E A \cos \theta

where

E is the intensity of the electric field

A is the surface

\theta is the angle between the direction of E and the perpendicular to the surface, whose direction is always outwards of the surface.


We can ignore the lateral surface of the cylinder, since the electric field is parallel to it, therefore the flux through the lateral surface of the cylinder is zero (because \theta=90^{\circ} and \cos \theta=0).


On the other two surfaces, the flux is equal and with opposite sign. In fact, on the first surface the flux will be

\Phi_1 = E \pi r^2

where r is the radius, and where we have taken \theta=0^{\circ} since the perpendicular to the surface is parallel to the direction of the electric field, so \cos \theta=1. On the second surface, however, the perpendicular to the surface is opposite to the electric field, so \theta=180^{\circ} and \cos \theta=-1, therefore the flux is

\Phi_2 = -E \pi r^2

And the net flux through the cylinder is

\Phi = \Phi_1 + \Phi_2 = E \pi r^2 - E \pi r^2=0

4 0
3 years ago
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