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2 years ago

12

4. The compound iron sulfide can be formed by

1 answer:

VladimirAG [237]2 years ago

6 0

Answer:

heating :))))))))))))))

Explanation:

the same as the last answer i posted... sorry it just came up in my recommended questions to answer

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Copper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f

Kruka [31]

Answer:

53.18 gL⁻¹

Explanation:

Given that:

$Cu^{2+}_{(aq)}$ $+$ $2NH_{3(aq)}$ $------>$ $[Cu(NH_3)_2]^+_{(aq)}$ ------equation (1)

where;

Formation Constant $(k_f) =$ $6.3*10^{10}$

However, the Dissociation of $CuBr_{(s)$ yields:

$CuBr_{(s)}$ ⇄ $Cu^{+}_{(aq)}$ $+$ $Br^-_{(aq)}$ -------------- equation (2)

where;

the Solubility Constant $(k_{sp})$ $= 6.3 *10^{-9$

From equation (1);

$(k_f) =$ $\frac{[[Cu(NH_3)_2]^+]}{[Cu^{2+}][NH_3]^{2}}$ --------- equation (3)

From equation (2)

$(k_{sp})$ $= [Cu^+][Br^-]$ --------- equation (4)

In $NH_3$ , the net reaction for $CuBr_{(s)$ can be illustrated as:

$CuBr_{(s)$ $+$ $2NH_{3(aq)}$ ⇄ $[Cu(NH_3)_2]^+_{(aq)}$ $+ Br^-_{(aq)}$

The equilibrium constant (K) can be written as :

$K=$ $\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}$

If we multiply both the numerator and the denominator with $[Cu^+]$ ; we have:

$K=$ $\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}*\frac{[Cu^+]}{[Cu^+]}$

$K=$ $\frac{[[Cu(NH_3)_2]^+}{[NH_3]^2[Cu^+]}*{[Cu^+][Br^-]}$

$K = k_f *k_{sp}$

$K= (6.3*10^{10})*(6.3*10^{-9})$

$K= 3.97*10^2$

$K$ ≅ $4.0*10^2$

Now; we can re-write our equilibrium constant again as:

$K=$ $\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}$

$4.0*10^2 = \frac{(x)(x)}{(0.76-2x)^2}$

$4.0*10^2 = \frac{(x)^2}{(0.76-2x)^2}$

$4.0*10^2 = (\frac{(x)}{(0.76-2x)})^2$

By finding the square of both sides, we have

$\sqrt {4.0*10^2} = \sqrt {(\frac{(x)}{(0.76-2x)})^2$

$2.0*10 = \frac{x}{(0.76-2x)}$

$20(0.76-2x) =x$

$15.2 -40x=x$

$15.2 = 40x +x$

$15.2 = 41x$

$x = \frac{15.2}{41}$

$x = 0.3707 M$

In gL⁻¹; the solubility of $CuBr_{(s)$ in 0.76 M $NH_3$ solution will be:

$= \frac{0.3707 mole of CuBr}{1L}*\frac{143.45 g}{mole of CuBr}$

= 53.18 gL⁻¹

4 0

2 years ago

What is the approximate total number of atoms in 1.0 mole of lithium?

chubhunter [2.5K]

Answer:

6.0 x 10 to the power of 23

6 0

2 years ago

What is the wavelength of radio waves? Which statement is true for a cooling curve? A. It shows how the temperature of the subst

ladessa [460]

Answer:

Most radio waves have wavelengths between 1 mm and 100 km.

A cooling curve shows A. how the temperature of a substance falls as heat is removed.

Explanation:

<em>Radio waves</em> are the longest of all the waves in the electromagnetic spectrum.

Most have wavelengths between 1 mm and 100 km, although there is no upper limit.

Some radio waves have wavelengths of 10 000 km.

A <em>cooling curve</em> (see image below) shows how the temperature of a substance falls as it is cooled.

In Option E., a decrease in temperature would cause an energy <em>loss</em>.

Options B., C., and D. involve the <em>addition of heat</em>.

5 0

3 years ago

If a reaction is completely neutralized, the products would have a pH of<br><br> PLEASE ANSWER!!!!

zysi [14]

Answer:

undefined

Explanation:

It depends on the type of reactants carrying out the reaction.

4 0

2 years ago

Can someone please help me with the correct formula for this?

Anarel [89]

Answer:

C₂H₄O

CH₃CHO

Explanation:

I'm not sure if you want the molecular formula or the condensed structure, but I will give you both.

Molecular formula:

You have 2 carbons (C₂), 4 hydrogens (H₄), and 1 oxygen (O). The molecular formula will be C₂H₄O.

Condensed Structure:

You have a carbon bonded to three hydrogens (CH₃). This carbon is bonded to a carbon that is bonded to a hydrogen and oxygen (CHO). The condensed structure will be CH₃CHO.

6 0

3 years ago