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Daniel [21]
3 years ago
8

9) If, after viewing a specimen at low power, you switch to high-dry power and, after using fine focus, cannot find the specimen

, what things could you do to help yourself (before asking the instructor to assist you
Physics
1 answer:
xeze [42]3 years ago
4 0

Answer:

See the answer below

Explanation:

<em>The best thing one can do in this case would be to return the microscope's objective to low power and then </em><em>re-center the specimen </em><em>before switching back to high-dry power.</em>

Most of the time, <u>what makes the specimen under the microscope to be out of focus at higher objective powers after being in focus at low power is because they are not properly centered on the stage</u>.  Hence, before calling on the instructor, it would be wise to first return to low power, re-center the specimen and bring it into focus after which the high power objective can be returned to and the fine focus adjusted to bring the image back to focus.

After doing the above and the specimen still does not come into focus, then the instructor can be called upon.

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Name the nutrients required for the<br>body.​
Anettt [7]

Answer:

1- water

2- fat

3- carbohydrates

4- vitamins

5- minerals

6 0
3 years ago
Cany anyone teach me how to use the vernier callipers?
luda_lava [24]
Place the object in between the two jaws such that they touch opposite ends of the object making sure the object is held firmly but don’t press too tight. If you need to measure an internal diameter, then insert the upper jaws in to the cavity and open them till they touch the sides. Tighten the locking screw to hold the jaws in position.

Note the position of the vernier scale zero on the main scale. The main scale reading is the division just before where the zero mark of the vernier scale is aligned. So is the zero mark aligns just after the fifth division between 3 and 4 the main scale reading is then 3.5.

The next step is to take the vernier scale reading. To do this find the mark on the vernier scale which lines up perfectly with a mark on the main scale. The vernier reading can then be found by multiplying the least value of the vernier scale with the number of divisions till that mark. For example if the least value is 0.01 mm and the 7thmark of the vernier scale is lined up perfectly then the vernier scale reading is 7 x 0.01 = 0.07.

The final step is to add the main scale and vernier readings to get the final measurement. For example 3.5 + 0.07 = 3.57 mm.

5 0
3 years ago
A rectangular certificate has a perimeter of 32 inches. Its area is 63 square inches. What are the dimensions of the certificate
irina1246 [14]
Perimeter = 2 ( L + W )
32 = 2 ( L + W )
16 = L + W
L = 16 - W

Area = L W
63 = L W
63 = (16-W) W
63 = 16W - W²
-W² + 16 W - 63 = 0
By factorizing W = 9 or W = 7
So the dimensions are 7 and 9
3 0
3 years ago
A 12.0 V car battery is being used to power the headlights of a car. Each of the two headlights has a power rating of 41.8 Watts
Marina CMI [18]

Answer:

n = 4.35 x 10¹⁹          

Explanation:

Given that

Voltage V= 12 V

Power rating of headlights = 41.8 W

We know that headlights of the car is connected in parallel connection.

We know that

Power = Current x Voltage

P = V I

I=\dfrac{41.8}{12}\ A

I=3.48  A

Therefore the total current will be

I'= 3.48 + 3.48 A

I = 6.96 A

We know that

Charge = Current x time

q= I' t

q= 6.96 x 1

q= 6.96 C

The charge on electron ,e= 1.6 x 10⁻¹⁹

q= n e

n=Number of electron

n=\dfrac{q}{e}

n=\dfrac{6.96}{1.6\times 10^{-19}}

n = 4.35 x 10¹⁹

5 0
3 years ago
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