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3 years ago

Which will not appear in the equilibrium constant expression for the reaction below

Chemistry

2 answers:

Sergeu [11.5K]3 years ago

4 0

Answer:

Your answer will be B. [C]

Explanation:

I am taking the test right now, and this answer choice is indeed correct.

Nana76 [90]3 years ago

3 0

Pure solids and liquids are not included in the equilibrium constant expression. This is because they do not affect the reactant amount at equilibrium in the reaction, so they are disregarded and kept at 1. Remember that the activity, a, of any solid or liquid in a reaction is equal to 1 oh yea can brainlest

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3 years ago

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3 years ago

The percent ionization of benzoic acid, 2.05 %, at a particular concentration is 25 °C. What was the concentration of benzoic ac

Mkey [24]

Answer : The concentration of benzoic acid in this solution was, 0.149 M

Explanation :

The balanced equilibrium reaction will be,

$C_6H_5COOH\rightleftharpoons C_6H_5COO^-+H^+$

initially conc. c 0 0

At eqm. c(1-α) cα cα

The expression for dissociation constant is:

$k_a=\frac{c\alpha\times c\alpha}{c(1-\alpha)}$

when α is very very small the, the expression will be,

$k_a=\frac{c^2\alpha^2}{c}=c\alpha^2$

Given:

α = 2.05 % = 0.0205

$K_a=6.3\times 10^{-5}$

Now put all the given values in this expression, we get:

$6.3\times 10^{-5}=c\times (0.0205)^2$

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3 years ago

If you have 30 grams of oxygen, how many atoms are present?

umka21 [38]

Answer:

1 × 10²⁴ atoms O

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

30 g O

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of O - 16.00 g/mol

Step 3: Convert

$30 \ g \ O(\frac{1 \ mol \ O}{16.00 \ g \ O} )(\frac{6.022 \cdot 10^{23} \ atoms \ O}{1 \ mol \ O} )$ = 1.12913 × 10²⁴ atoms O

Step 4: Check

We are given 1 sig fig. Follow sig fig rules and round.

1.12913 × 10²⁴ atoms O ≈ 1 × 10²⁴ atoms O

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3 years ago