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natima [27]
3 years ago
13

Which will not appear in the equilibrium constant expression for the reaction below

Chemistry
2 answers:
Sergeu [11.5K]3 years ago
4 0

Answer:

Your answer will be B. [C]

Explanation:

I am taking the test right now, and this answer choice is indeed correct.

Nana76 [90]3 years ago
3 0
<span>Pure solids and liquids are not included in the equilibrium constant expression. This is because they do not affect the reactant amount at equilibrium in the reaction, so they are disregarded and kept at 1. Remember that the activity, a, of any solid or liquid in a reaction is equal to 1 oh yea can brainlest</span>
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n a gas-phase equilibrium mixture of SbCl5, SbCl3, and Cl2 at 500 K, pSbCl5 = 0.17 bar and pSbCl3 = 0.22 bar. Calculate the equi
Lorico [155]

Answer:

2.7 × 10⁻⁴ bar

Explanation:

Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

Kp = pSbCl₃ × pCl₂ / pSbCl₅

pCl₂ = Kp × pSbCl₅ / pSbCl₃

pCl₂ = 3.5 × 10⁻⁴ × 0.17 / 0.22

pCl₂ = 2.7 × 10⁻⁴ bar

7 0
3 years ago
You have 350 mL of 3.4 M hydrochloric acid (HCl). How many grams of HCl gas are dissolved? Bonus: what is the volume of the HCl
Crank

Answer:

1. 43.44g of HCl

2. 26.67 L of HCl

Explanation:

1) Molarity of a solution = number of moles (n) ÷ Volume (V)

According to the provided information in this question,

V = 350 mL = 350/1000 = 0.350L

Molarity = 3.4 M

Using Molarity = n/V

3.4 = n/0.350

n = 3.4 × 0.350

n = 1.19mol

Using the formula below to calculate the mass of HCl;

mole = mass/molar mass

Molar mass of HCl = 1 + 35.5 = 36.5g/mol

mole = mass/MM

mass = 1.19 mol × 36.5g/mol

mass = 43.44g of HCl

2) At STP, HCl has a pressure of 1atm, a temperature of 273K

V = ?

n = 1.19 mol

R = 0.0821 Latm/molK

Using PV = nRT

V = nRT/P

V = 1.19 × 0.0821 × 273/1

Volume = 26.67L

5 0
3 years ago
Some magnesium powder was mixed with some copper( II)oxide and heated strongly. there was a victorious reaction producing a lot
-BARSIC- [3]

Reaction:

\mathrm{Mg \: + \: CuO \rightarrow Cu\: + \: MgO}

Magnesium is a stronger reducing agent than copper and is thus able to reduce copper(II) oxide.

Products of the reaction: Magnesium oxide and metallic copper.

4 0
3 years ago
Read 2 more answers
Why is it important for you to bring your line of sight down to the level of the meniscus?
Aleksandr-060686 [28]

Answer:

If you are not eye to eye with the miniscus you would be reading wrong because you have to read right from the middle because of you won’t you’d always be off

Explanation:

4 0
2 years ago
Which of the following explains why there are so many differences in the properties of peptides and proteins?
Brrunno [24]
I think the answer is a). There are 20 kinds of amino acid can form peptides and proteins. There are many possible combinations. And there are also different folding forms and structure that can lead differences in properties.
5 0
3 years ago
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