Answer:
The answer to your question is: 2.75 x 10 ²¹ atoms
Explanation:
Data
H₃PO₄
mass = 0.1488 g
MW H₃PO₄ = 3 + 31 + (16 x 4) = 98g
98 g of H₃PO₄ ------------------ 3 g of H₂
0.1488 g H₃PO₄ --------------- x
x = 0.0046 g of H₂
1 g of H₂ ------------------- 6.023 x 10²³ atoms
0.0046 g of H₂ -------------- x
x = (0.0046 x 6.023 x 10²³) / 1
x = 2.75 x 10 ²¹ atoms
Answer:
12.7 mol
Explanation:
<em>A chemist measures the amount of fluorine gas produced during an experiment. He finds that 482. g of fluorine gas is produced. Calculate the number of moles of fluorine gas produced.</em>
Step 1: Given data
Mass of fluorine (m): 482. g
Step 2: Determine the molar mass (M) of fluorine
Fluorine is a diatomic molecule of chemical formula F₂. Its molar mass is:
mF₂ = 2 × mF = 2 × 19.00 g/mol = 38.00 g/mol
Step 3: Determine the number of moles (n) corresponding to 482. g of fluorine
We will use the following expression,.
n = m/M
n = 482. g/(38.00 g/mol)
n = 12.7 mol
Answer:
The concentration of the Cu²⁺ solution in the 10,0 mL volumetric flask is 5,425×10⁻³ M Cu²⁺
Explanation:
The first dilution from a 2,17M Cu²⁺ solution gives:
2,17 M Cu²⁺ ×
= <em>0,0217 M Cu²⁺solution</em>
<em />
The second dilution gives as concentration:
0,0217 M Cu²⁺ ×
= 5,425×10⁻³ M Cu²⁺ solution
I hope it helps!
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Answer:
d
Explanation:
HF gives its H to HPO42 making it H2PO4, so HF is the acid and F- is the conj base
