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Vlada [557]
3 years ago
10

For a science project, Janet performs four experiments that are supposed to show a chemical reaction. She displays her results i

n a table.A 4-column table with 4 rows. The first column titled experiment has entries 1, 2, 3, 4. The second column titled substances has entries water + heat, vinegar + baking soda, cabbage juice + lemon juice, liquid A + liquid B. The third column titled evidence of reaction has entries gas formation, gas formation, color change, precipitate formation. The fourth column titled Chemical Reaction ? has entries yes, yes, yes, yes.In the column titled "Chemical reaction?,” which experiment’s data should be changed to "No”?Experiment 1Experiment 2Experiment 3Experiment 4
Chemistry
1 answer:
g100num [7]3 years ago
5 0

Answer:

Experiment 1

Explanation:

I don’t know if this is right

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Please help, this assignment is to hard for me. :(
iren [92.7K]

Answer:

603000 J

Explanation:

The following data were obtained from the question:

Energy required (Q) =...?

Mass (M) = 10000 g

Specific heat capacity (C) = 2.01 J/g°C

Overheating temperature (T2) = 121°C

Working temperature (T1) = 91°C

Change in temperature (ΔT) =.?

Change in temperature (ΔT) =T2 – T1

Change in temperature (ΔT) = 121 – 91

Change in temperature (ΔT) = 30°C

Finally, we shall determine the energe required to overheat the car as follow:

Q = MCΔT

Q = 10000 × 2.01 × 30

Q = 603000 J

Therefore, 603000 J of energy is required to overheat the car.

7 0
3 years ago
Predict whether or not a precipitate forms upon mixing 175.0 mLmL of a 0.0055 MKClMKCl solution with 145.0 mLmL of a 0.0015 MM A
Lorico [155]

Answer:

AgCl

Explanation:

The reaction of KCl (In aqueous phase K⁺ + Cl⁻) with AgNO₃ ((In aqueous phase Ag⁺ + NO₃⁻) produce:

Ag⁺ + Cl⁻ ⇄ AgCl(s)

The reaction has a k of 5.56x10¹⁰

That means you will produce 5.56x10¹⁰ molecules of AgCl per molecule of Ag⁺ and Cl⁻ in solution.

As the AgCl is in solid state, this molecules is the precipitate.

I hope it helps!

4 0
3 years ago
Write the balanced equation for the combustion of isooctane to produce water vapor and carbon dioxide gas.Assuming gasoline is i
tangare [24]

Answer:

The yield is 16 moles of CO2 per 2 moles of isooctane.

The mass of CO2 is 1.15 billion tonnes

Explanation:

First we set the unbalanced equation:

C_{8}H_{18} + O_{2} \longrightarrow CO_{2} + H_{2}O

Now we proceed to balance the equation:

2C_{8}H_{18} + 25O_{2} \longrightarrow 16CO_{2} + 18H_{2}O

With the equation balanced, we see that the theoretical yield is 16 moles of CO2 per 2 moles of isooctane and we can proceed to make calculations with the following data:

\rho _{C_{8}H_{18}}=0.69 g/mL\\Consumption: 142.86x10^{9} gal\\1gal=3785.41 mL\\M_{C_{8}H_{18}}=114.23g/mole\\M_{CO_{2}}=44.01g/mole\\

Knowing the different relations between mass, density and molar mass, we have the following results:

V_{C_{8}H_{18}}=5.41x10^{14}mL\\m_{C_{8}H_{18}}=3.73x10^{14}g\\n_{C_{8}H_{18}}=3.27x10^{12}mole\\n_{CO_{2}}=2.62x10^{13}mole\\m_{CO_{2}}=1.15x1015g\\m_{CO_{2}}=1.15x10^{9}tonnes

8 0
4 years ago
22. A flask containing 450 mL of 0.50 M H2SO4 was accidentally knocked to the floor. How many grams of NaHCO, do you need to put
Dvinal [7]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

To calculate the moles of a solute, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of sulfuric acid = 450mL = 0.45 L      (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 0.5 moles/ L

Putting values in above equation, we get:

0.5mol/L=\frac{\text{Moles of sulfuric acid}}{0.45L}\\\\\text{Moles of sulfuric acid}=0.225mol

For the given chemical reaction:

H_2SO_4(aq.)+2NaHCO_3(aq.)\rightarrow Na_2SO_4(aq.)+2H_2O(l)+2CO_2(g)

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of sodium bicarbonate.

So, 0.225 moles of sulfuric acid will react with = \frac{2}{1}\times 0.225=0.45mol of sodium bicarbonate

To calculate the mass of sodium bicarbonate, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of sodium bicarbonate = 0.45 moles

Molar mass of sodium bicarbonate = 84.007 g/mol

Putting values in above equation, we get:

0.45mol=\frac{\text{Mass of sodium bicarbonate}}{84.007g/mol}\\\\\text{Mass of sodium bicarbonate}=38g

Hence, the correct answer is Option D.

7 0
3 years ago
What is true about water that is freezing?
Liono4ka [1.6K]
It is going through a physical change
4 0
3 years ago
Read 2 more answers
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