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gladu [14]
3 years ago
12

A tiger paces back and forth along the front of its cage, which is 8 m wide. The tiger starts from the right side of the cage, p

aces to the left side, then back to the right side, and finally back to the left. What total distance has the tiger paced? What is the tiger's resultant displacement?
Physics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer:

The total distance is 24 m.

The tiger's resultant displacement is 8 m.

Explanation:

Given that,

Width of tiger= 8 m

Tiger starts from the right side of the cage,

Paces to the left side

\Delta x_{1}=+8\ m

Then, back to the right side,

\Delta x_{2}=-8\ m

finally, back to the left

\Delta x_{3}=+8\ m

We need to calculate the total distance covered

Using formula of distance

d= x_{1}+x_{2}+x_{3}

Put the value into the formula

d=8+8+8

d=24\ m

We need to calculate the tiger's resultant displacement

Using formula of displacement

D=\Delta x_{1}+\Delta x_{2}+\Delta x_{3}

Put the value into the formula

D=8+(-8)+8

D=8\ m

Hence, The total distance is 24 m.

The tiger's resultant displacement is 8 m.

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No distance is the length between two routes

Explanation:

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A car is traveling on the highway at 28 m/s The driver sees a tree in the middle of the road and slams on the brakes. The car co
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3 years ago
1) A person having a mass of 59.1 kg stands before a flight of 30 stairs each of which is 25.0 cm high. He runs up 20 stairs, tu
poizon [28]

Answer:

P = 147,75 W

Explanation:

A man whose mass is 59.1kg climbs up 30 steps of a stair each step is 25 cm high

Height at 30 steps , h=30×2.5=  7.5 m

Change in potential energy , =mgh=59.1×10×7.5 = 4432.5 J

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P = 4432.5 /30

P = 147,75 W

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3 0
2 years ago
Violet light of wavelength 405 nm ejects electrons with a maximum kinetic energy of 0.890 eV from a certain metal. What is the b
AleksandrR [38]

Answer:

  Ф = 2.179 eV

Explanation:

This exercise has electrons ejected from a metal, which is why it is an exercise on the photoelectric effect, which is explained assuming the existence of energy quanta called photons that behave like particles.

            E = K + Ф

the energy of the photons is given by the Planck relation

            E = h f

we substitute

           h f = K + Ф

           Ф= hf - K

the speed of light is related to wavelength and frequency

            c = λ f

            f = c /λ

            Φ = \frac{hc}{\lambda } - K

let's reduce the energy to the SI system

            K = 0.890 eV (1.6 10⁻¹⁹ J / 1eV) = 1.424 10⁻¹⁹ J

calculate

           Ф = 6.63 10⁻³⁴ 3 10⁸/405 10⁻⁹  -1.424 10⁻¹⁹

           Ф = 4.911 10⁻¹⁹ - 1.424 10⁻¹⁹

           Ф = 3.4571 10⁻¹⁹ J

         

we reduce to eV

           Ф = 3.4871 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

           Ф = 2.179 eV

4 0
2 years ago
A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the
ser-zykov [4K]

Answer:

The maximum length during the motion is L_{max} = 1.45m

Explanation:

From the question we are told that

           The mass  is  m =0.5 kg

            The vertical spring  length is  L = 1.10m

            The unstretched  length is  L_{un} = 1.30m

          The initial speed is v_i = 1.3m/s

          The new length of the spring L_{new} =  1.30 m

The spring constant k is mathematically represented as

                           k = -\frac{F}{y}

Where F is the force applied  = m * g = 0.5 * 9.8=4.9N

           y is the difference in weight which is   =1.10-0.50=0.6m

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

    Now  substituting values accordingly

                    k =  \frac{4.9}{0.6}

                       = 8.17 N/m

The  elastic potential energy is given as E_{PE} = \frac{1}{2} k D^2

  where D is this the is the displacement  

Since Energy is conserved the total elastic potential energy would be

             E_T = initial  \ elastic\ potential \ energy + kinetic \ energy

            E_T = \frac{1}{2} k D_{max}^2 =   \frac{1}{2} k D^2 + \frac{1}{2} mv^2

Substituting value accordingly

                \frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2

                4.085 * D_{max}^2 = 3.69

                 D^2_{max} = 0.9033

                D_{max} = 0.950m

So to obtain total length we would add the unstretched length

 So we have

                  L_{max} = 0.950 + 0.5 = 1.45m

                               

               

               

                 

                     

5 0
3 years ago
Read 2 more answers
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