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vredina [299]
3 years ago
11

Classify each statement as a property of ethers, alcohols, or both ethers and alcohols?

Chemistry
1 answer:
natita [175]3 years ago
8 0

Explanation:

1. Only alcohols forms hydrogen bond  between themselves and with other compounds containing an O-H, N-H, or F-H bond, such as water.

2. Alcohols up to 4 carbons are miscible in water because they have hydrogen bonded to oxygen and can form hydrogen bond with water. However, it is not possible for ethers.

3. When comparing ethers and alcohols of similar molecular weights, ethers have lower boiling point than alcohol. This is because of the presence of hydrogen bond in alcohols.

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Determine the mass of the H2CO3 produced.
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During a laboratory experiment, a 2.36-gram sample of NaHCO3 was thermally decomposed. In this experiment, carbon dioxide and wa
eduard

Answer:

  • 90.7 %

Explanation:

<u>1) Chemical equation (given)</u>

  • 2NaHCO₃ → Na₂CO₃ + H₂CO₃

<u>2) Theoretical yield</u>

<u>a) Convert mass of NaHCO₃ to moles:</u>

  • n = mass in grams / molar mass
  • molar mass = 84.007 g/mol
  • n = 2.36 g / 84.007 g/mol = 0.02809 mol

<u>b) Mole ratio:</u>

  • 2 mol NaHCO₃ : 1 mol H₂CO₃

<u>c) Proportionality:</u>

  • 2 mol NaHCO₃ / mol H₂CO₃ = 0.02809 mol NaHCO₃ / x

       ⇒ x = 0.2809 / 2 mol H₂CO₃ = 0.01405 mol H₂CO₃

<u>3) Actual yield</u>

<u>a) Mass balance</u>: 2.36 g - 1.57 g = 0.79 g

<u>b) Convert 0.79 g of carbonic acid to number of moles</u>:

  • n = mass in grams / molar mass

  • molar mass = 62.03 g/mol

  • n = 0.79 g / 62.03 g/mol = 0.01274 mol

<u>4) Percentage yield, y (%)</u>

  • y (%) = actual yield / theoretical yield × 100

  • y (%) = 0.1274 mol / 0.1405 mol × 100 = 90.68%

The answer must show 3 significant figures, so y(%) = 90.7%.

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3 years ago
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