Complete question:
Coal gasification consists of the chemical transformation of solid coal into gas. The heating values of coal differ, but the higher the heating value, the higher the value of the gas produced (which is essentially methane, carbon monoxide, hydrogen, etc.). The following coal has a reported heating value of 29,770 KJ/Kg as received. Assuming that this is the gross heating value, calculate the net heating value.. Component__________Percent C___________________71
H2__________________5.6
N2__________________1.6
S____________________2.7
Ash__________________6.1
O2___________________13
Answer:
LHV = 28478.8 KJ/kg
Explanation:
The gross heating value is also the higher heating value (HHV), while the net heating value is the lower heating value (LHV).
This involves the conversion from higher heating value (HHV) to lower heating value(LHV).
Let's use the formula:
LHV = HHV - 0.212H - 0.0245M - 0.008A
We are given
HHV = 29,770 KJ/kg = 29.770MJ/kg
H = hydrogen% =5.6%
A = oxygen% = 13%
M = 0
Substituting the figures in the formula, we have:
LHV = 29.770 - 0.212*5.6 - 0.0245*0 - 0.008*13
= 29.770 - 1.1872 - 0 - 0.104
= 28.4788 MJ/kg
= 28478.8 KJ/kg
LHV = 28478.8 KJ/kg
The net heating value, LHV = 28478.8 KJ/kg
A. The substance dissolved. Just because a substance dissolved in a solvent doesn’t mean that a chemical action occurred. For example, if you put sugar in water as stir, it will dissolve, but the chemical make up of the sugar and the water don’t change. A chemical reaction can be indicated by a drastic change in color or temperature or if a substance precipitate.
Hope this helped :)
For average speed, we divide the total distance covered by the total time taken.
After doing that, you will see that Jane has the lowest average speed.
Answer:
0.1593 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have two different values of V and T:
<em>P₁V₁T₂ = P₂V₂T₁</em>
<em></em>
P₁ = 600 torr/760 = 0.789 atm, V₁ = 185.0 mL = 0.185 L, T₁ = 25.0°C + 273 = 298.0 K.
P₂ (at STP) = 1.0 atm, V₂ = ??? L, T₂ (at STP = 0.0°C) = 0.0°C + 273 = 273.0 K.
<em>∴ V₂ = P₁V₁T₂/P₂T₁</em> = (0.789 atm)(0.185 mL)(298.0 K)/(1.0 atm)(273.0 K) = <em>0.1593 L.</em>
Regard the principle of utilization of two gas.
Make a consistent control of hardware containing gas.
Make a consistent control of weight diminishing valves giving gas.
No smoking zone.
