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AysviL [449]
3 years ago
8

An object with a mass of 15 kg accelerates 10.0 m/s2 when an unknown force is applied to it. What is the

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

f=mass × acceleration

=15×10

=150

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a motorcycle is capable of accelerating at 5.1 m/s starting from rest how far can it travell in 1.5 sec
Katarina [22]
The answer is 21m because the motion is in one dimension with constant acceleration.

The initial velocity is 0, because it started from rest, the acceleration <span>ax</span> is <span>4.7<span>m<span>s2</span></span></span>, and the time t is <span>3.0s</span>

Plugging in our known values, we have

<span>Δx=<span>(0)</span><span>(3.0s)</span>+<span>12</span><span>(4.7<span>m<span>s2</span></span>)</span><span><span>(3.0s)</span>2</span>=<span>21<span>m</span></span></span>

5 0
3 years ago
7. An object can be accelerating even if its speed is
steposvetlana [31]

Answer:

I think that the answer might be d

4 0
2 years ago
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A solar cooker, really a concave mirror pointed at the Sun, focuses the Sun's rays 13.8 cm in front of the mirror. Part A What i
shepuryov [24]

From the concept of optics on a curvature of a spherical mirror, the proportion for which the focal length is equivalent to half the radius of curvature is fulfilled. Mathematically this is

f = \frac{R}{2}

Here,

f = Focal Length

R = Radius

Rearranging to find the radius we have,

R = 2f

Replacing with our values,

R = 2(13.8cm)

R = 27.6cm

Therefore the radius of the spherical surface from which the mirror was made is 27.6cm

6 0
2 years ago
Which statements best describe the work of Marie and Pierre Curie? Check all that apply.
AleksAgata [21]

B. They came up with the term “radioactivity.”

C. They conducted experiments with uranium-containing minerals and pure uranium.

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4 0
3 years ago
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You have two vectors, which are 2.59 m at 30.0° north of east and 4.18 m at 60.0° north of west. What is the magnitude in meters
andrew11 [14]

Answer:\ec{r}=0.153\hat{i}+4.914\hat{j}v

Explanation:

Given

Vector 1

\vec{a}=2.59\left ( cos30\hat{i}+sin30\hat{j}\right )

Vector 2

\vec{b}=4.18\left ( -cos60\hat{i}+sin60\hat{j}\right )

Resultant \vec{r}=\vec{a}+\vec{b}

\vec{r}=2.59\left ( cos30\hat{i}+sin30\hat{j}\right )+4.18\left ( -cos60\hat{i}+sin60\hat{j}\right )

\vec{r}=0.153\hat{i}+4.914\hat{j}

|r|=4.916

5 0
3 years ago
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