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nataly862011 [7]

2 years ago

15

A professional golfer walks at an at an average rate of 4.20 meters per second on the golf course. The amount of time required f

or her to walk from the tee to the green 622 meters away is

1 answer:

Alja [10]2 years ago

5 0

Answer:

T try d add b CD c

Explanation:

Cdgffd

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Two tiny beads are 25 cm apart with no other charges or fields present. Bead A carries 10 µC of charge and bead B carries 1 µC.

steposvetlana [31]

The electric forces on both beads are equal.

3 0

3 years ago

Read 2 more answers

whats an isotope? give the number of protons, neutrons, and electrons in a neutral atom of each of the following isotopes, Carbo

melamori03 [73]

Isotopes refer to different atoms of the same element (i.e. same number of protons) that differ in the number of neutrons they have (giving them different atomic weights). Atomic weight is the sum of protons and neutrons (each contributes 1 atomic mass unit).

Carbon has 6 protons by definition. If you have a carbon-13 atom (the 13 referring to its mass), the atom has 13 - 6 = 7 neutrons. Since it's neutral, protons = electrons, so there are also 6 electrons.

Sulfur has 16 protons by definition. If you have a sulfur-32 atom, the atom has 32 - 16 = 16 neutrons. Since it's neutral, protons = electrons, so there are also 16 electrons.

8 0

3 years ago

A person wants to make a metronome for music practice. He uses a 35-g object attached to a spring to serve as the time standard.

alukav5142 [94]

To develop this problem it will be necessary to apply the concepts related to the frequency of a spring mass system, for which it is necessary that its mathematical function is described as

$f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}$

Here,

k = Spring constant

m = Mass

Our values are given as,

$m = 35g = 35*10^{-3}kg$

$f = 1 Hz$

Rearranging to find the spring constant we have that,

$k = (2\pi f \sqrt{m})^2$

$k = 4\pi^2 f^2 m$

$k = (4) (\pi)^2 (1) (35*10^{-3})$

$k = 1.38N/m$

Therefore the spring constant is 1.38N/m

7 0

3 years ago

If the pressure exerted on a 300.0 mL sample of hydrogen gas at constant temperature is increased from 0.500 kPa to 0.750 kPa, w

uranmaximum [27]

Answer:

200 mL

Explanation:

Given that,

Initial volume, V₁ = 300 mL

Initial pressure, P₁ = 0.5 kPa

Final pressure, P₂ = 0.75 kPa

We need to find the final volume of the sample if pressure is increased at constant temperature. It is based on Boyle's law. Its mathematical form is given by :

$V\propto \dfrac{1}{P}\\\\P_1V_1=P_2V_2$

V₂ is the final volume

$V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{300\times 0.5}{0.75}\\\\V_2=200\ mL$

So, the final volume of the sample is 200 mL.

5 0

2 years ago

Bx = -1.33 m and By = 2.81 m<br> Find the magnitude of the<br> vector.

NISA [10]

Answer:

Explanation:

The formula for the magnitude of a vector is

$B_{mag}=\sqrt{(-1.33)^2+(2.81)^2}$ and then round to the hundredths place:

3.11 m. Since we are in Q2, we can also find the direction of this vector:

$tan^{-1}(\frac{2.81}{-1.33})=-64.7$ but since we are in Q2, we add 180 degrees to the result, getting the angle to be 115.3

3 0

2 years ago