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Lerok [7]
2 years ago
5

Determine the activity of the sample of cerium when the sample was 80 seconds old

Physics
1 answer:
Artemon [7]2 years ago
8 0

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A force of 4 kg weight acts on a body of mass 9.8 kg calculate the acceleration
White raven [17]

Answer:

here given is a weight

then force becomes mg

that is F=Mg

=4*9.8

then by using the formula

F=Ma

a=F/M

=4*9.8/9.8

=4

Explanation:

3 0
3 years ago
Read 2 more answers
a team of dogs is pulling a sled with a net force of 2000 N. The sled is accelerating a 2.2 m/s^2. What is the mass of the sled?
sweet-ann [11.9K]
Force, F = ma

Where m = mass in kg, a = acceleration in m/s²,  Force, F is in N.

F = ma

2000 = m*2.2

2.2m = 2000

m = 2000/2.2

m ≈ 909.09

Mass is ≈ 909.09 kg.
5 0
3 years ago
If Juan upgrades from a sports car to a large truck, what will happen to the
Brrunno [24]

Answer:

The force must increase

Explanation:

According to newton's second law "force is the product of mass and acceleration".

      Force  = mass  x acceleration

Now, the mass of the sports car is lesser compared to that of the truck. Therefore, to take both automobiles to the same speed, enough force must be applied by the engine of the truck.

There must be an increase in the force in order to make both automobiles attain the same speed.

5 0
2 years ago
How does the observed pitch of the buzzer change as it moves
andriy [413]

The answer is

Pitch of the buzzer increased (higher tone) as it moves towards the observer

5 0
2 years ago
A spherical gas-storage tank with an inside diameter of 9 m is being constructed to store gas under an internal pressure of 1.50
lutik1710 [3]

Answer: 33 mm

Explanation:

Given

Diameter of the tank, d = 9 m, so that, radius = d/2 = 9/2 = 4.5 m

Internal pressure of gas, P(i) = 1.5 MPa

Yield strength of steel, P(y) = 340 MPa

Factor of safety = 0.3

Allowable stress = 340 * 0.3 = 102 MPa

σ = pr / 2t, where

σ = allowable stress

p = internal pressure

r = radius of the tank

t = minimum wall thickness

t = pr / 2σ

t = 1.5*10^6 * 4.5 / 2 * 102*10^6

t = 0.033 m

t = 33 mm

The minimum thickness of the wall required is therefore, 33 mm

6 0
3 years ago
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