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nataly862011 [7]
3 years ago
12

Ampere showed that parallel wires carrying current in the same direction would_____ each other.

Chemistry
2 answers:
aliya0001 [1]3 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

It is known that flow of electrons is known as current. Also, we know that electrons carry a negative charge.

Therefore, when parallel wires carrying current in the same direction then due to the same charge there will be repulsion between the electrons.

Thus, we can conclude that Ampere showed that parallel wires carrying current in the same direction would repel each other.

sveticcg [70]3 years ago
5 0

Answer:

The answer is "Repel". Opposite forces attract and equal positioned forces repel, checked it too.

Explanation:

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lisov135 [29]

Answer:

0.07172 L = 7.172 mL.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT. </em>

where, P is the pressure of the gas in atm (P = 1.0 atm, Standard P).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 3.2 x 10⁻³ mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 273 K, Standard T).

<em>∴ V = nRT/P =</em> (3.2 x 10⁻³ mol)(0.0821 L.atm/mol.K)(273 K)/(1.0 atm) = <em>0.07172 L = 7.172 mL.</em>

8 0
4 years ago
Draw a Lewis structure for [H3O]+. Show all unshared pairs and the formal charges, if any.
Montano1993 [528]

Answer: Formal Charges: Hydrogen = 0 and Oxygen = +1

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Explanation:

The attachment below shows the Lewis structure and the calculations

3 0
3 years ago
1. Mixing is a physical change.<br> True or false
Hitman42 [59]

Answer:

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Answer:

4

Explanation:

Ionization energy can be defined as the energy required for an atom to lose its valence electron to form an ion. Hence, it deals with how easily an atom would lose its electron and form an ion. As the valence electrons are lossless bound to the outermost shell, they can easily be lost without much problem or better still they can be lost easily. Hence, the energy change here is small and thus we can conclude that the ionization energy here is low.

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3 years ago
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