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2 years ago

How many moles of Chlorine gas are required to produce 5.35 moles of NaCl in this reaction?

Chemistry

1 answer:

meriva2 years ago

5 0

Answer:

2.675 moles of Chlorine gas are required

Explanation:

Chlorine gas, Cl2, reacts with NaBr to produce NaCl and Br2 as follows:

Cl2 + 2NaBr → 2NaCl + Br2

<em>Where 1 mole of chlorine gas produce 2 moles of NaCl</em>

<em />

Thus, to produce 5.35 moles of NaCl are required:

5.35mol NaCl * (1mol Cl2 / 2mol NaCl) =

<h3>2.675 moles of Chlorine gas are required</h3>

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Therefore, the percentage reduction in intensity is 79.80 %

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