How many moles of Chlorine gas are required to produce 5.35 moles of NaCl in this reaction?

Chemistry

1 answer:

meriva2 years ago

5 0

Answer:

2.675 moles of Chlorine gas are required

Explanation:

Chlorine gas, Cl2, reacts with NaBr to produce NaCl and Br2 as follows:

Cl2 + 2NaBr → 2NaCl + Br2

<em>Where 1 mole of chlorine gas produce 2 moles of NaCl</em>

<em />

Thus, to produce 5.35 moles of NaCl are required:

5.35mol NaCl * (1mol Cl2 / 2mol NaCl) =

<h3>2.675 moles of Chlorine gas are required</h3>

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earnstyle [38]

Answer:

The frequency is $f = 2,01 * 10^{15} \ Hz$

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$E_a = \frac{E_b}{N_A}$

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