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saw5 [17]
3 years ago
12

Please please help please please help me please please help please please

Chemistry
1 answer:
Kitty [74]3 years ago
5 0

Answer:

Boron phosphide (BP) is a chemical compound of boron and phosphorus. It is a semiconductor. Contents. 1 History; 2 Appearance; 3 Chemical properties .

Explanation:

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When a chemist titrates a standard solution of 168.61 mL of hydrochloric acid (HCl) with 0.104 M sodium hydroxide (NaOH) , she f
ch4aika [34]
The conc of NaOH is 0.104M which means that 1000mL solution contains 0.104mol of NaOH, so the amount of moles used in the titration will be
\frac{0.104mol}{1000mL} * 259.4mL = 4.00* 10^{-7} mol
The reaction of NaOH and HCl is one to one so the moles of HCl that were titrated will also be 4.00* 10^{-7} mol
The Molarity is therefore
\frac{4.00* 10^{-7} mol}{168.61 mL} * 1000mL = 2.38* 10^{-6} M
4 0
3 years ago
A certain substance is a poor conductor of electricity and has a high melting point this substance is most likely
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B) as it is ionic, so has strong ionic bonds between molecules, but ions cant move so charge cant move through the material, meaning it can't conduct electricity very well

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4 years ago
A 15.0 mL sample of a liquid has a mass of 12.3 g. What is the density of the liquid? A. 0.820g/mL B. 1.22g/mL C. 185g/mL D. 12.
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Explanation:

Mass = 12.3 g

Volume = 15mL

Density = Mass /volume

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Which substances will make a salt when combined?
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4 0
4 years ago
Read 2 more answers
Determine the volume of carbon dioxide gas produced at STP when 2.5 g of nitroglycerin decomposes by this balanced equation. 4C3
PolarNik [594]

Answer:

0.67 L

Explanation:

Given data:

Volume of carbon dioxide = ?

Mass of nitroglycerine = 2.5 g

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Solution:

Chemical equation:

4C₃H₅N₃O₉    →    12CO₂ + 10 H₂O + 6N₂ + O₂

Number of moles of nitroglycerine:

Number of moles = mass/ molar mass

Number of moles =  2.4 g/ 227.1 g/mol

Number of moles = 0.01 mol

Now we will compare the moles of  nitroglycerine and carbon dioxide from balance chemical equation.

             C₃H₅N₃O₉          :         CO₂

                 4                     :           12

                0.01                :      12/4×0.01 = 0.03 mol

Volume of CO₂:

PV = nRT

V = nRT/P

V = 0.03 mol×  0.0821 atm.L/mol.K× 273.15 K / 1 atm

V = 0.67 L

4 0
3 years ago
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