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What’s is the mass in grams of 5.90 mol C8H18?

DerKrebs [107]

Mass = 5.90 x 114 = 672.6g.

This can be rounded to 673g

C = 12 grams x 8 = 96 grams

H = 1 gram x 18 = 18 grams

Total = 96 + 18 = 114 grams in one mole.

If you have 5.9 moles, multiply this by the weight of one mole (114 grams) = 672.6 rounded to 673 grams in 5.9 moles.

4 0

3 years ago

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What is the structure of carbon

expeople1 [14]

Answer:

With an atomic number of 6 (six electrons and six protons), the first two electrons fill the inner shell, leaving four in the second shell. Therefore, carbon atoms can form four covalent bonds with other atoms to satisfy the octet rule.

Explanation:

With an atomic number of 6 (six electrons and six protons), the first two electrons fill the inner shell, leaving four in the second shell. Therefore, carbon atoms can form four covalent bonds with other atoms to satisfy the octet rule.

3 0

3 years ago

Copper is used for electrical wirin g and cooking pans however iron is much more common on earth than copper why might copper be

pishuonlain [190]

Because copper has a higher electrical and thermal conductivity than iron and is not susceptible to oxidation as easily.

8 0

3 years ago

Uranium-236 is _____. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-

nata0808 [166]

Uranium-236 is intermediate nuclei. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-bomb.

Following is the reaction involved in above process:

 $^{235}U$ + $^{1}n$ → $^{236}U$ → $^{144}Ba$ + $^{89}Kr$ + 3 $^{1}n$ + 177 MeV

Here,
$^{235}U$ = Fission material,
$^{1}n$ = projectile,
$^{236}U$ = intermediate nuclei,
$^{144}Ba$ and $^{89}Kr$ = Fission product

8 0

3 years ago

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if the percent by volume is 2% and the volume of solution is 250 mL what is the volume of solute and solution

Liula [17]

Answer:

Solute = 5 mL; solution = 250 mL

Explanation:

The formula for percent by volume is

$\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%$

If you have 250 mL of a solution that is 2 % v/v,

$\begin{array}{rcl}2 \, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\2 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{2 \times 250\text{ mL}}{100}\\\\ & = & \textbf{5 mL}\\\end{array}$

If there is no change of volume on mixing,

Volume of solution = 250 mL

-Volume of solute = 5

Volume of solvent = 245 mL

5 0

3 years ago