2 J / 4 C = 1/2 joule per coulomb.
That's 1/2 volt.
The correct expression for the maximum speed of the object during its motion is
.
<h3>
Maximum speed of the object</h3>
The maximum speed of the object is determined using the following formulas;
v(max) = Aω
where;
- A is the amplitude of the motion
- ω is angular speed
The maximum speed of the object can also be obtained from the maximum net force on the object,
F = ma
where;
- F is the maximum net force
- a is the acceleration
- m is mass of the object
F = m(v/t)
mv = Ft
v = Ft/m
Thus, the correct expression for the maximum speed of the object during its motion is
.
Learn more about maximum speed here: brainly.com/question/4931057
1/2*2.8*x^{2}=2.8*9.81*1.50
X=5.425
Because K.E=1/2*M*V² and it is equal to P.E in the conservation of energy which means its K.E=P.E
P.E=m*g*h
So K.E equals 1/2*2.8*(5.425)²=41.20