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ANTONII [103]
2 years ago
8

Calculate the mass of CaCL2 formed when 5 moles of chlorine reacts with calcium metal....

Chemistry
1 answer:
OLEGan [10]2 years ago
8 0

Answer:

555 g of CaCl₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Ca + Cl₂ —> CaCl₂

From the balanced equation above,

1 mole of Cl₂ reacted to produce 1 mole of CaCl₂.

Next, we shall determine the number of mole of CaCl₂ produced by the reaction of 5 moles of Cl₂. This can be obtained as follow:

From the balanced equation above,

1 mole of Cl₂ reacted to produce 1 mole CaCl₂.

Therefore, 5 moles of Cl₂ will also react to produce 5 moles of CaCl₂.

Thus, 5 moles of CaCl₂ were obtained from the reaction.

Finally, we shall determine the mass of 5 moles of CaCl₂. This can be obtained as follow:

Mole of CaCl₂ = 5 moles

Molar mass of CaCl₂ = 40 + (35.5×2)

= 40 + 71

= 111 g/mol

Mass of CaCl₂ =?

Mass = mole × molar mass

Mass of CaCl₂ = 5 × 111

Mass of CaCl₂ = 555 g

Therefore, 555 g of CaCl₂ were obtained from the reaction.

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Explanation:
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3 0
3 years ago
Calculate the mole fraction of the total ions in an aqueous solution prepared by dissolving 0.400 moles of CaI2 in 850.0 g of wa
Evgesh-ka [11]

Answer:

0.00840

Explanation:

The computation of the mole fraction is as follow:

As we know that

Molar mass = Number of grams ÷ number of moles

Or

number of moles = Number of grams ÷ molar mass

Given that

Number of moles of CaI2 = 0.400

And, Molar mass of water = 18.0 g/mol

Now  Number of moles of water is

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= 47.22 mol

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= 47.62

So, Molar fraction of CaI2 is

= 0.400 ÷ 47.62

= 0.00840

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Explanation:

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3 years ago
Read 2 more answers
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