C. K since it is above Aluminium in the reactivity series
Answer: The answer is D
Explanation:
In a chemical equilibrium, the forward and reverse reactions occur at equal rates, and the concentrations of products and reactants remain constant. A catalyst speeds up the rate of a chemical reaction, but has no effect upon the equilibrium position for that reaction.
Answer:
The volume of oxygen will be 168 dm³.
Explanation:
Given data:
mass of methane = 56 g
volume of oxygen = ?
Solution:
First of all we will write the balance chemical equation.
CH₄ + 2O₂ → CO₂ + 2H₂O
Now we will calculate the moles of methane:
number of moles = mass / molar mass
number of moles = 56 g / 16 g/mol
number of moles = 3.5 mol
Now we will compare the moles of oxygen and methane.
CH₄ : O₂
1 : 2
3.5 : 3.5 × 2 = 7
The moles of oxygen are 7 mol.
Now we will calculate the volume of oxygen. The gas is at room temperature and pressure so, one mole of gas will occupy 24 dm³ volume and 7 mole will occupy,
7 × 24 dm³ = 168 dm³