Answer:
547.7 g of C₆H₁₂O₆
Solution:
The balance chemical equation is as follow,
C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O
According to equation,
6 moles of O₂ burns = 180.56 g of C₆H₁₂O₆
So,
18.2 moles of O₂ will burn = X g of C₆H₁₂O₆
Solving for X,
X = (18.2 mol × 180.56 g) ÷ 6 mol
X = 547.7 g of C₆H₁₂O₆
Percent composition by mass is calculated (mass of element within compound)/(mass of compound)*100. The lower the total molar mass of the compound, the greater the percent composition of sulfur. In this case, MgS would be that compound, since Mg has the lowest molar mass of the four elements bonded to S.
That would be cause part of the sodium is pure and that means it still kind of has it properties when it was an element and that its i think.
Answer:
in the wire last one is right
