Answer:
near the equator where it's hot
<span>1.40 x 10^5 kilograms of calcium oxide
The reaction looks like
SO2 + CaO => CaSO3
First, determine the mass of sulfur in the coal
5.00 x 10^6 * 1.60 x 10^-2 = 8.00 x 10^4
Now lookup the atomic weights of Sulfur, Calcium, and Oxygen.
Sulfur = 32.065
Calcium = 40.078
Oxygen = 15.999
Calculate the molar mass of CaO
CaO = 40.078 + 15.999 = 56.077
Since 1 atom of sulfur makes 1 atom of sulfur dioxide, we don't need the molar mass of sulfur dioxide. We merely need the number of moles of sulfur we're burning. divide the mass of sulfur by the atomic weight.
8.00 x 10^4 / 32.065 = 2.49 x 10^3 moles
Since 1 molecule of sulfur dioxide is reacted with 1 molecule of calcium oxide, just multiply the number of moles needed by the molar mass
2.49 x 10^3 * 56.077 = 1.40 x 10^5
So you need to use 1.40 x 10^5 kilograms of calcium oxide per day to treat the sulfur dioxide generated by burning 5.00 x 10^6 kilograms of coal with 1.60% sulfur.</span>
Answer:
B) decreasing entropy is a non-spontaneous process
Explanation:
Answer: 67 mmHg
Explanation:
According to Dalton's Gas Law, the total pressure of a mixture of gases is the sum of the pressure of each individual gas.
i.e Ptotal = P1 + P2 + P3 + .......
In this case,
Ptotal = 512 mmHg
P(oxygen) = 332 mmHg
P(carbon mono-oxide) = 113 mmHg
Remaining pressure (P3) = ?
To get P3, apply Dalton's Gas Law formula
Ptotal = P(oxygen) + P(carbon mono-oxide) + P3
512 mmHg = 332 mmHg + 113 mmHg + P3
512 mmHg = 445 mmHg + P3
P3 = 512 mmHg - 445 mmHg
P3 = 67 mmHg
Thus, the remaining pressure is 67 mmHg
I choose the option A.
The electron absorbs energy from specific wavelength then moving from a lower energy orbital to a higher energy orbital.
