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bixtya [17]
3 years ago
13

A crate is pulled 7 m across a smooth surface. The tension in the rope pulling the crate is 40 N. If the work on the crate is 24

7 J, what is the angle the rope makes with the horizontal
Physics
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

<em>61.9°</em>

Explanation:

The formula for calculating the workdone is expressed as

Workdone = Fdsin theta

F is the force applied on the crate

d is the distance covered

theta is the angle that the rope makes with the horizontal

Given

F = 40N

d = 7m

Workdone = 247J

Substituting into the formula:

247 = 40(7)sin theta

247 = 280sin theta

sin theta = 247/280

sin theta = 0.88214

theta = arcsin(0.88214)

theta = 61.9°

<em>Hence the angle that the rope makes with the horizontal is 61.9°</em>

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How do I figure work done using W=Fd when I have a mass of 61.09kg, weight of 599.79N, d=153cm, and t=4.52s?
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3 years ago
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