A crate is pulled 7 m across a smooth surface. The tension in the rope pulling the crate is 40 N. If the work on the crate is 24
7 J, what is the angle the rope makes with the horizontal
1 answer:
Answer:
<em>61.9°</em>
Explanation:
The formula for calculating the workdone is expressed as
Workdone = Fdsin theta
F is the force applied on the crate
d is the distance covered
theta is the angle that the rope makes with the horizontal
Given
F = 40N
d = 7m
Workdone = 247J
Substituting into the formula:
247 = 40(7)sin theta
247 = 280sin theta
sin theta = 247/280
sin theta = 0.88214
theta = arcsin(0.88214)
theta = 61.9°
<em>Hence the angle that the rope makes with the horizontal is 61.9°</em>
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