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3 years ago

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a spring has a spring constant of 80N/m. How much energy is stored in the spring when it is compressed 0.2m past it's natural le

ngth?

1 answer:

Alex73 [517]3 years ago

7 0

Answer:

1.6 J (Joules)

Explanation:

Since the potential energy of a spring can be found from the equation PE = 1/2 * k * x^2, the PE is 1/2 * 80 *.2^2 = 1.6 J

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A 52 kg child on a swing is travelling at 6 m/s . What is his gravitational potential energy if he has 1000 J of the mechanical

DiKsa [7]

Answer:

The correct answer is "64 J".

Explanation:

The given values are:

Mass,

m = 52 kg

Velocity,

v = 6 m/s

Mechanical energy,

= 1000 J

Now,

The gravitational potential energy will be:

⇒ $P.E=1000-\frac{1}{2}mv^2$

$=1000-\frac{1}{2}\times 52\times (6)^2$

$=1000-26\times 36$

$=1000-936$

$=64 \ J$

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3 years ago

Describe the full water cycle

sergey [27]

The water cycle (hydro-logic cycle), explains the constant motion of water on, above and below the surface of the Earth. The mass of water on Earth stays equally constant over time, although the severe portion of the water goes into the major reservoirs of ice, fresh water, saline water and atmospheric water is variable depending on a wide range of climatic variables. The water moves from one reservoir to another, such as from river to ocean, or from the ocean to the atmosphere, by the physical processes of evaporation, condensation, precipitation, infiltration, surface runoff, and subsurface flow. In doing so, the water goes through different forms: liquid, solid (ice) and vapor.

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3 years ago

A 234.0 g piece of lead is heated to 86.0oC and then dropped into a calorimeter containing 611.0 g of water that initally is at

Vaselesa [24]

Answer: $24.70 ^{\circ}C$

Explanation:

Given

mass of lead piece $m_l=234 gm\approx 0.234 kg$

mass of water in calorimeter $m_w=611 gm\approx 0.611 kg$

Initial temperature of water $T_w=24^{\circ}C$

Initial temperature of lead piece $T_l=24^{\circ}C$

we know heat capacity of lead and water are $125.604 J/kg-k$ and $4.184 kJ/kg-k$ respectively

Let us take $T ^{\circ}C$ be the final temperature of the system

Conserving energy

heat lost by lead=heat gained by water

$m_lc_l(T_l-T)=m_wc_w(T-T_w)$

$0.234\times 125.604(86-T)=0.611\times 4.184\times 1000(T-24)$

$86-T=\frac{0.611\times 4.184\times 1000}{29.391}(T-24)$

$86-T=86.97T-2087.49$

$T=\frac{2173.491}{87.97}=24.70^{\circ}C$

3 0

3 years ago

Hello please help i’ll give brainliest

ser-zykov [4K]

The correct answer is B.Antartica and Australia were one landmass millions of years ago.

5 0

3 years ago

Two thin conducting plates, each 56.0 cm on a side, are situated parallel to one another and 7.0 mm apart. If 10^-10 electrons a

dsp73

Answer:

$E=576.5V/m$

Explanation:

From the question we are told that:

Length $l=56.0cm=0.56m$

Distance apart $d=7.0mm=0.007m$

Electron Transferred $n=10^{-10}$

Therefore

Total Charge

Since Charge on each electron is

$e=1.602*10^{-19}$

Therefore

$T=1.602*10^{-19} *10^{10}$

$T=1.602*10^{-9}$

Generally the equation for Charge density is mathematically given by

$\rho=T/A$

Where

Area

$A=0.56*0.56$

$A=0.3136$

Therefore

$\rho=1.602*10^{-9}/0.3136$

$\rho=5.10*10^{-9}$

Generally the equation for Electric Field in the capacitor is mathematically given by

$E=\frac{\rho}{e_0}$

$E=\frac{5.10*10^{-9}}{8.85x10{-12}}$

$E=576.5V/m$

8 0

3 years ago