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almond37 [142]
3 years ago
9

2. Spiderman has a mass of 80 kg. He is suspended from a thin strand of his super-awesome spidey-web. The greatest tension the s

trand can withstand without breaking is 824 N. What is the maximum acceleration with which Spiderman can safely climb up the strand?
Physics
1 answer:
AysviL [449]3 years ago
3 0

Answer:

10.3m/s2

hope that helped, if yes give me brainliest and if no draw my attention by hitting the comment section

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Within which type of system is the total energy conserved?
pychu [463]

Answer:

B

Explanation:

connected and is B

hope thats the best

7 0
3 years ago
A car, of mass 2.1 X 10^3 kg, travels in the horizontal plane around an unbanked curve of a radius of 275 m at a speed of 26 m/s
Nadusha1986 [10]

Answer:

Centripetal force is perpendicular to velocity and causes uniform circular motion. ... force exerted on a 900.0-kg car that negotiates a 500.0-m radius curve at 25.00 m/s. ... A car moving at 96.8 km/h travels around a circular curve of radius 182.9 m ... Because the car does not leave the surface of the road, the net vertical force ...

Explanation:

HE monda

4 0
3 years ago
1. If you add air to a flat tire through a single small entry hole, why does the air spread out to fill the tire?
ikadub [295]

Answer:

The tire fills up just like anything else that holds air when u pump a ball or tire up it fills all the way up cause it is a small confined space and after filling it with air the atoms of the air fill the tire up

Explanation:

7 0
3 years ago
Nature of components of mixture should be known to separate the mixture why?​
Anna [14]

Answer:

It is important to be able to separate mixtures to obtain a desired component from the mixture and to be able to better understand how each component.

Explanation:

8 0
3 years ago
A 60-kg rollerblader rolls 10 m down a 30? incline. When she reaches the level floor at the bottom, she applies the brakes. The
VARVARA [1.3K]

Answer:

s = 20 m

Explanation:

given,

mass of the roller blader = 60 Kg

length = 10 m

inclines at = 30°

coefficient of friction = 0.25

using conservation of energy

\dfrac{1}{2}mu^2 = m g d sin \theta

u^2 = 2 g d sin30^0

u= \sqrt{2\times 9.8 \times 10 sin30^0}

u = 9.89 m/s

Using second law of motion  

ma =μ mg

a = μ g

a = 0.25 x 9.8

a = 2.45 m/s²

Using third equation of motion ,  

v² - u² = 2 a s

0² - 9.89² = 2 x 2.45 x s

s = 20 m

the distance moved before stopping is 20 m

3 0
4 years ago
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