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Tatiana [17]
3 years ago
14

Write the expressions for the equilibrium constants of the reactions below.

Chemistry
1 answer:
Bond [772]3 years ago
8 0

In general, for a given chemical reaction in equilibrium

aA  + bB  \rightleftharpoons cC  + dD

the equilibrium constant, Keq, will be

K_{eq}=\frac{\mathrm{[C]^c}[D]^d}{\mathrm{[A]^a[B]^b}}.

Usually, only aqueous and gaseous species are included in the equilibrium constant; the concentration of any pure solid or liquid is omitted. While the states of the reactants and products in the reactions for this problem aren't given, these three particular reactions all happen to be ones where they can (and, in fact, do) occur where all the species are in the gaseous state. So, all the reactants and product(s) are included in the equilibrium constants below, but this will not always be the case.

a.

K_{eq}=\frac{\mathrm{[NH_3]^2}}{\mathrm{[N_2][H_2]^3}}

b.

K_{eq}=\frac{\mathrm{[HBr]^2}}{\mathrm{[Br][H_2]}}

c.

K_{eq}=\frac{\mathrm{[H_2][CO_2}]}{\mathrm{[CO][H_2O]}}

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Which characteristic is given by the angular momentum quantum number?
chubhunter [2.5K]

Answer:

orbital shape.

Explanation:

1) There are four quantum numbers to describe the electrons. These are:

i) Principal quantum number (n)

ii) Azimuthal quantum number (ℓ), also called angular momentum quantum number.

iii) Magnetic quantum number (m)

iv) Spin quantum number (s)

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It tells the kind of orbital, which is its shape

The correspondence is:

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1 = p orbital,

2 = d orbital,

3 = f orbital.

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3 0
2 years ago
If a sample of magnesium with a mass of 35.0 grams reacts with 35.0 grams of oxygen how much magnesium oxide will be produced?​
slamgirl [31]

Answer:

58.0 g of MgO

Explanation:

in a perfect world, 70 g, however we don't live in a perfect world

The equation of reaction

2Mg + O₂ --> 2MgO

first find which element is limiting:

35 g x 1 mol/24.3 g of Mg x 2 mol of MgO/ 2 mole of Mg = 1.44 moles of MgO

35 g x 1 mol/32g of Mg x 2 mol of MgO/ 1 mole of O₂ = 2.1875 moles of MgO

This means Mg is the limiting factor, so you will be using this moles to find grams of MgO

1.44 mols of MgO x 40.3 g of MgO/ 1 mol = 58.0 g of MgO

8 0
3 years ago
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