Question

A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How many radians did the disk turn while stopping ? C. how many revolutions? ​

Answer 1

Answer:

Explanation:

30 rev/min (2π rad/rev) / (60 s/min) = π rad/s

α = Δω/t = (0 - π)/3 = π/3 rad/s²

θ = ½αt² = ½(π/3)3² = 1.5π radians

θ = 1.5π rad/2π rad/rev = 0.75 rev