A car battery is a 12V DC source. Typically you will find a fuse that can handle a 7 amp surge to power on the lights in your ca
r. What resistance is that fuse protecting?*'
2 answers:
<h2>Answer: </h2>
<u>By Ohm's law, Resistance comes</u>
V = IR
R = V/I
R = 12/7
<u>R = 1.71</u><u>Ω</u><u>.</u>
Answer:
resistance=power/current=12/7=1.71ohm
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Answer:
note:
<u><em>solution is attached due to error in mathematical equation. please find the attachment</em></u>
Referred to as Carrier Frequency
Answer:
7/7
Explanation:
7/56 ÷1
7/56÷ 7/7
7/56 ×7/7
1/8
Answer:
121.6 volts
Explanation:
V = IR
V = (3.8 A)(32 Ω) = 121.6 volts