Given the measured value of mass M in the experiment the error in 2M is ; dM
<u>Given data :</u>
Measured value of mass M = ( 0.743 ± 0.005 ) kg
<h3>The error in 2M in the measured value </h3>
The error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM
Hence we can conclude that the measured value of mass M in the experiment the error in 2M is ; dM.
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Answer:
The acceleration of the object is
Explanation:
Given:
Initial velocity of object = 200 feet/second
Final velocity of object = 50 feet/second
Time of travel = 5 seconds
To calculate acceleration of the object we will find the rate of change of velocity with respect to time.
So, acceleration is given by:
where represents final velocity, represents initial velocity and is time of travel.
Plugging in values to evaluate acceleration.
The acceleration of the object is (Answer). The negative sign shows the object is slowing down.
<em>The displacement of an object during a specific unit of time: </em>Velocity (the direction is part of displacement.)
<em>How fast or slow an object is moving and in what direction: </em>Velocity (speed & direction)
<em>How fast or slow an object is moving: </em>Speed (no direction)
<em>A cheetah running 97 km/h: </em>Speed (no direction)
<em>A train traveling 45 m/s north: </em>Velocity (speed & direction)
Fnet = m x a
= 65kg x 0.3m/s^2
= 19.5N
This is assuming that there is no friction or other external forces!