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Mamont248 [21]
3 years ago
6

Two charges are repelling each other with a force magnitude F. If each charge doubled and the distance between the charges becam

e four times the original distance, determine the new magnitude of the force. (1/2)F 4F 2F 16 F (1/4)F
Physics
1 answer:
eduard3 years ago
7 0

Answer:

(1/4)F

Explanation:

Let F be the force on charges q and q' separated by a distance, d

F = kqq'/d²

Now, if q and q' are doubled, our new charges are 2q and 2q' respectively and, if the distnace is increased by four times, then our new distance is 4d. So our new force F' = k (2q)(2q')/(4d)²

= 4kqq'/16d²

= kqq'/4d²

= F/4

So, the magnitude of our new force is F/4

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The current in the wires of a circuit is 180.0 milliamps. If the resistance of the circuit were doubled ( with no change in volt
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Explanation:

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Now, we replace the values of the first current into the equation

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Then we have that the resistance is doubled so we have this new equation:

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7 0
3 years ago
The amount of gas that a helicopter uses is directly proportional to the number of hours spent flying. the helicopter flies for
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Answer:

The helicopter uses 35 gallons to fly for 5 hours.

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The amount of gas that a helicopter uses for flying varies directly proportional to the number of hours spent flying.

g ∝ T

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\therefore \frac{g_1}{g_2}=\frac{T_1}{T_2}

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\Rightarrow \frac{28}{g_2}=\frac{4}{5}

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The helicopter uses 35 gallons to fly for 5 hours.

5 0
3 years ago
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