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Stels [109]
3 years ago
12

An unbanked (flat) curve of radius 150 m is rated for a maximum speed of 32.5 m/s. At what maximum speed, in m/s, should a flat

curve with radius of 65.0 m be rated
Physics
1 answer:
Rasek [7]3 years ago
3 0

Answer:

The maximum speed is 21.39 m/s.

Explanation:

Given;

radius of the flat curve, r₁ = 150 m

maximum speed, v_{max} = 32.5 m/s

The maximum acceleration on the unbanked curve is calculated as;

a_c_{max} = \frac{V_{max}^2}{r} \\\\a_c_{max} = \frac{32.5^2}{150} \\\\a_c_{max} = 7.04 \ m/s^2

the radius of the second flat curve, r₂ = 65.0 m

the maximum speed this unbanked curve should be rated is calculated as;

a_c_{max} = \frac{V_{max}^2}{r_2} \\\\V_{max}^2 = a_c_{max}  \ \times \ r_2\\\\V_{max} = \sqrt{a_c_{max}  \ \times \ r_2} \\\\V_{max} =\sqrt{7.04 \ \times \ 65} \\\\V_{max} = 21.39 \ m/s

Therefore, the maximum speed is 21.39 m/s.

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Radio Waves

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<h2>Answer: Transpiration </h2>

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2 years ago
A rocket car is developed to break the land speed record along a salt flat in Utah. However, the safety of the driver must be co
Naddika [18.5K]

Answer:

a = 45 m/s/s

Explanation:

As we know that total mass of the rocket is

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total mass of the fuel is given as

m = 2000 kg

all the fuel is burnt in 15 s

so rate of the fuel burning is given as

\frac{dm}{dt} = \frac{2000}{15}

\frac{dm}{dt} = 133.33 kg/s

now the thrust force on the rocket is given as

F_{th} = v\frac{dm}{dt}

(6000 - 133.33 t) a = (900 + v)(133.33)

so we have

\frac{dv}{900 + v} = (133.33)\frac{dt}{6000 - 133.33 t}

so we have

ln(\frac{900 + v}{900}) = - ln(\frac{6000 - 133.3 t}{6000})

1 + \frac{v}{900} = \frac{6000}{6000 - 133.3 t}

now acceleration is rate of change in velocity

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3 years ago
Bruce pulls a spring with a spring constant k=100 Nmk=100\, \dfrac{\text N}{\text m}k=100mN​k, equals, 100, start fraction, star
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Answer:

K_{e} = 2.0 J

Explanation:

In this exercise you are asked to calculate the elastic potential energy of a spring

          K_{e} = ½ k x²

where k is the spring constant and x is the displacement from equilibrium position

In this exercise, indicate that the spring constant is k = 100 N/m, the length at rest is  x₀ = 20 cm = 0.20 m, up to the position x₁ = 40 cm = 0.40 m, therefore the elongation

           Δx = x₁ - x₀

           Δx = 0.40 - 0.20

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3 years ago
While the resistance of the variable resistor in the left-hand solenoid is decreased at a constant rate, the induced current thr
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Answer:

<em>The induced current through resistor R will</em>

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The image is shown below, and the full question is written down as

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Since the current in the left-hand solenoid flows in an anticlockwise direction, then it will have an equivalent magnetic polarity of a north pole on a magnet.

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