Answer:
acceleration = 2.4525 m/s²
Explanation:
Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²
Tension in the rope = T
Sol: m2 > m1
i) for downward motion of m2:
m2 a = m2 g - T
5 a = 5 × 9.81 m/s² - T
⇒ T = 49.05 m/s² - 5 a Eqn (a)
ii) for upward motion of m1
m a = T - m1 g
3 a = T - 3 × 9.8 m/s²
⇒ T = 3 a + 29.43 m/s² Eqn (b)
Equating Eqn (a) and(b)
49.05 m/s² - 5 a = T = 3 a + 29.43 m/s²
49.05 m/s² - 29.43 m/s² = 3 a + 5 a
19.62 m/s² = 8 a
⇒ a = 2.4525 m/s²
Answer:
Without units, the results are unclear and it is hard to keep track of what each seperate measurement entails.
Answer:
P = 1401.4 x 10⁶ W
Explanation:
Given that
Water flow rate m = 2.2 x 10⁶ kg/s
Height ,h= 65 m
Acceleration due to gravity ,g= 9.8 m/s²
The power P is given as
P= m g h
P=Power
m=Water flow rate
h=height
Now by putting the values in the above equation
P = 2.2 x 10⁶ x 9.8 x 65 W
P = 1401.4 x 10⁶ W
Therefore the power wasted will be 1401.4 x 10⁶ W.
