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Digiron [165]
3 years ago
10

In order for photosynthesis to take place what must be present?

Chemistry
2 answers:
PIT_PIT [208]3 years ago
8 0

Answer:

water carbon dioxide sunlight and the plant

Explanation:

Ksju [112]3 years ago
4 0

Answer:

For photosynthesis to take place, plants need to take in carbon dioxide (from the air), water (from the ground) and light (usually from the sun)

Explanation:

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What are the 4 things attached to the center carbon in all amino acids?
aev [14]
amino group
carboxyl group
R-group
single Hydrogen arom
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3 years ago
HELP ME ASAP TO GET BRAINLYYYY!!!!
Elina [12.6K]

Answer:

B C A

Explanation:

because as you pour the blue stuff in it will straight up go to the bottom (and has less blue coloring) Then it will go to the top (lil more blue coloring) then eventually the whole jar will be blue

hope this helps you out bro

5 0
3 years ago
Read 2 more answers
20. You are approaching a downhill. Which configuration woulo
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Answer: I think the answer is A

Explanation:

I’m sorry if I’m wrong.

4 0
2 years ago
If you had a 0.800 L solution containing 0.0240 M of Fe3+(aq), and you wished to add enough 1.38 M NaOH(aq) to precipitate all o
guapka [62]

Answer:

0.041 L = 41.3 mL

Explanation:

This problem we will solve by considering the stoichiometry of the reaction and the definition of molarity.

Number of moles in .800 L solution:

0.800 L x 0.0240 M = 0.800 L x .0240 mol/L = 0.0192  mol Fe³⁺

to form the precipitate Fe(OH)₃ we will need 3 times .0192

mol NaOH required = 0.057

given the concentration of 1.38 mol M NaOH we can calculate how many milliliters of NaOH will contain 0.057 mol:

1.L/1.38 mol NaOH x 0.057 mol NaOH = 0.041 L

0.041 L x 1000 mL/1L = 41.3 mL

7 0
3 years ago
A 30.00 mL sample of HBr was titrated using 0.1756 M NaOH. Determine the concentration of the HBr sample if 17.52 mL of NaOH was
postnew [5]

<u>Answer:</u> The concentration of HBr sample is 0.1025 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HBr

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=30.00mL\\n_2=1\\M_2=0.1756M\\V_2=17.52mL

Putting values in above equation, we get:

1\times M_1\times 30.00=1\times 0.1756\times 17.52\\\\M_1=\frac{1\times 0.1756\times 17.52}{1\times 30.00}=0.1025M

Hence, the concentration of HBr sample is 0.1025 M

5 0
3 years ago
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