Answer:
197.07 K
Explanation:
To solve this problem we can <u>use the PV=nRT equation</u>, where:
- P = 205 kPa ⇒ 205 * 0.00986 = 2.02 atm
- V = 0.0120 m³ ⇒ 0.0120 * 1000 = 12 L
- R = 0.082 atm·L·mol⁻¹·K⁻¹
We<u> input the data</u>:
- 2.02 atm * 12 L = 1.50 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T
And <u>solve for T</u>:
CH4 + 2O2 = CO2 + 2H2O
According to molar weights :
16 gm CH4 + 64 gm O2 = 44 gm CO2 + 36 gm H2O
Since 16 gm CH4 produce 36 gm H2O
Hence 2.5 gmCH4 produce 36×2.5/16 gm H2O
= 5.265 gm of H2O
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