Net force = mass x acceleration = 250 x 3 = 750 N
Kinetic energy because the horse is in motion
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The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
- The value of F₀ so that string 1 remains vertical is approximately <u>0.377·M·g</u>
<h3>How can the equilibrium of forces be used to find the value of F₀?</h3>
Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
The weight of the rod is at the middle.
Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;

Which gives;


F₀ = T₂·sin(37°)
Which gives;

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Learn more about equilibrium of forces here:
brainly.com/question/6995192