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ludmilkaskok [199]
3 years ago
15

4-year-old becomes frightened of the dark and refuses to go to sleep at night. How would a psychoanalyst and a behaviorist diffe

r in their views of how this problem developed?
Physics
1 answer:
inessss [21]3 years ago
8 0

Answer:

A psychoanalyst would see the 4-year-old as having an unresolved conflict where the brain judges or evaluates how good or bad the darkness is, or the usefulness of sleeping in the dark at night based on a comparison, due to the child's exploration of the world around him. A psychoanalyst might see the child's refusal to sleep at night due to the dark as a fear created for instance when the child sleeps alone without the parent. This might change if the child sleeps at night beside the parent in the dark.

While behaviorists would look at how having previous negative experiences in the dark influences a child's behavior towards staying in the dark. This fear would be reinforced with more negative experiences in the dark such as having a bad nightmare whenever the child sleeps in the dark, a feeling of hearing, or seeing strange things while in the dark. These examples would have built a behavioral pattern where the child would be conditioned to respond fearfully to being in the dark.

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What could be the possible answer to the question ?<br><br>thankyou ~​
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The value of the force, F₀, at equilibrium is equal to the horizontal

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Response:

  • The value of F₀ so that string 1 remains vertical is approximately <u>0.377·M·g</u>

<h3>How can the equilibrium of forces be used to find the value of F₀?</h3>

Given:

The weight of the rod = The sum of the vertical forces in the strings

Therefore;

M·g = T₂·cos(37°) + T₁

The weight of the rod is at the middle.

Taking moment about point (2) gives;

M·g × L = T₁ × 2·L

Therefore;

T_1 = \mathbf{\dfrac{M \cdot g}{2}}

Which gives;

M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}

T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})}  = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}

F₀ = T₂·sin(37°)

Which gives;

F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2}  \approx  \mathbf{0.377  \cdot M \cdot g}

  • F₀ ≈ <u>0.377·M·g</u>

<u />

Learn more about equilibrium of forces here:

brainly.com/question/6995192

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2 years ago
Read 2 more answers
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