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ludmilkaskok [199]
3 years ago
15

4-year-old becomes frightened of the dark and refuses to go to sleep at night. How would a psychoanalyst and a behaviorist diffe

r in their views of how this problem developed?
Physics
1 answer:
inessss [21]3 years ago
8 0

Answer:

A psychoanalyst would see the 4-year-old as having an unresolved conflict where the brain judges or evaluates how good or bad the darkness is, or the usefulness of sleeping in the dark at night based on a comparison, due to the child's exploration of the world around him. A psychoanalyst might see the child's refusal to sleep at night due to the dark as a fear created for instance when the child sleeps alone without the parent. This might change if the child sleeps at night beside the parent in the dark.

While behaviorists would look at how having previous negative experiences in the dark influences a child's behavior towards staying in the dark. This fear would be reinforced with more negative experiences in the dark such as having a bad nightmare whenever the child sleeps in the dark, a feeling of hearing, or seeing strange things while in the dark. These examples would have built a behavioral pattern where the child would be conditioned to respond fearfully to being in the dark.

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Two resistors, R1 and R2, are
dlinn [17]

The reciprocal of the total resistance is equal to the sum of the reciprocals of the component resistances:

1/(120.7 Ω) = 1/<em>R₁</em> + 1/(221.0 Ω)

1/<em>R₁</em> = 1/(120.7 Ω) - 1/(221.0 Ω)

<em>R₁</em> = 1 / (1/(120.7 Ω) - 1/(221.0 Ω)) ≈ 265.9 Ω

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3 years ago
Based on Newton’s 3rd Law of motion, if an archer shoots an arrow at the target, the action force is the bowstring against the a
maw [93]

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maybe target, not sure.

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You measure the velocity of a drag racer that accelerates with constant acceleration. You want to plot the data and determine th
Ivenika [448]

Answer:

a) Linear equation

Explanation:

Definition of acceleration

a=\frac{dv}{dt}\\

if a=constant and we integrate the last equation

v(t)=v_{o}+a*t

So the relation between the time and the velocity is linear. If we plot the velocity in function of time, the plot is a line, and the acceleration is the slope of this line.

8 0
3 years ago
A diver stands on a diving platform 10.0 m above the surface of a pool and leaps upward with an initial speed of 2.5 m/s. how fa
Alexus [3.1K]
<span>The diver is heading downwards at 12 m/s Ignoring air resistance, the formula for the distance under constant acceleration is d = VT - 0.5AT^2 where V = initial velocity T = time A = acceleration (9.8 m/s^2 on Earth) In this problem, the initial velocity is 2.5 m/s and the target distance will be -7.0 m (3.0 m - 10.0 m = -7.0 m) So let's substitute the known values and solve for T d = VT - 0.5AT^2 -7 = 2.5T - 0.5*9.8T^2 -7 = 2.5T - 4.9T^2 0 = 2.5T - 4.9T^2 + 7 We now have a quadratic equation with A=-4.9, B=2.5, C=7. Using the quadratic formula, find the roots, which are -0.96705 and 1.477251164. Now the diver's velocity will be the initial velocity minus the acceleration due to gravity over the time. So V = 2.5 m/s - 9.8 m/s^2 * 1.477251164 s V = 2.5 m/s - 14.47706141 m/s V = -11.97706141 m/s So the diver is going down at a velocity of 11.98 m/s Now the negative root of -0.967047083 is how much earlier the diver would have had to jump at the location of the diving board. And for grins, let's compute how fast he would have had to jump to end up at the same point. V = 2.5 m/s - 9.8 m/s^2 * (-0.967047083 s) V = 2.5 m/s - (-9.477061409 m/s) V = 2.5 m/s + 9.477061409 m/s V = 11.97706141 m/s And you get the exact same velocity, except it's the opposite sign. In any case, the result needs to be rounded to 2 significant figures which is -12 m/s</span>
7 0
3 years ago
A shearing of 50N is applied to an aluminum rod with a length of 10m a cross sectional area of 1.0×10-5 and a shear modulus of 2
slega [8]

Answer:

0.002 m or 2 mm

Explanation:

Given that:

Force, F = 50N

Area = 1 * 10^-5

Length, L = 10m

Shear modulus, = 2.5 * 10^10

Using the relation ;

D = (50 ÷ 1*10^-5) ÷ (2.5 * 10^10 ÷ 10)

D = 5000000 ÷ 2.5 * 10^9

D = 5 * 10^6 ÷ 2.5 * 10^9

D = (5/2.5) * 10^(6-9)

D = 2 * 10^-3

D = 0.002 m

1m = 1000 mm

0.002m = (1000 * 0.002) = 2 mm

7 0
3 years ago
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