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mestny [16]
3 years ago
8

Imagine That Kevin can instantly transport himself between Planet X and planet Y. Which statement could be said about Kevin in t

his situation
Physics
1 answer:
Svetradugi [14.3K]3 years ago
7 0

When Kevin pulls off this stunt, his average speed is (distance) / (time).

So, whatever the distance may be, his average speed for the trip is

(some distance)/0 = infinite speed.

Now, stay with me here:

His acceleration at the beginning of the trip is

(change in speed) / (time to change)

Whatever speed he started at, his acceleration had to be

(infinite change in speed)/(no time).

That's a big acceleration doncha know.

He needed an infinite force and an infinite amount of energy from somewhere to achieve that acceleration, and as soon as he started accelerating, his insides got totally shredded.

Whatever arrived on Planet-Y looked like a pile of overcooked pasta.

It wasn't worth the trip.

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An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object
MariettaO [177]

Answer:

\boxed {\boxed {\sf a=42.8 \ m/s^2}}

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

a=\frac{v-u}{t} (<em>v </em>is the final velocity, <em>u</em> is the initial velocity, <em>t </em>is the time).

The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:

v=236 \ m/s\\u=22 \ m/s\\t= 5 \ s

Substitute the values into the formula.

a=\frac{236 \ m/s - 22 \ m/s}{5 \ s}

Subtract in the numerator.

  • 236 m/s-22 m/s=214 m/s

a=\frac{214 \ m/s}{5 \ s}

Divide.

a=42.8 \ m/s^2

The acceleration of the object is <u>42.8 meters per square second.</u>

6 0
3 years ago
A stone is thrown vertically upwards with an initial velocity 20m/s. Find the maximum height it reaches and the time taken by it
Len [333]

Answer:

The maximum height it reaches will be 20 m.

The time taken by it to reach the height will be: t = 2 seconds.

Explanation:

We know the equation of the motion under gravity

v² - u² = 2gs

u = initial velocity = 20 m/s

v = final velocity = 0 m/s

s\:=\:h_{max}

so

v^{2} \:-\:u^{2} \:=\:2gs

substituting u = 20 m/s, v = 0 m/s, g = -10 and s\:=\:h_{max}

\left(0\right)^2-\:\left(20\right)^2=\:2\left(-10\right)\times h_{max}

2\left(-10\right)\times h_{max}=-400

\frac{2\left(-10\right)h_{max}}{-20}=\frac{-400}{-20}

\:h_{max}=20 m

Therefore, the maximum height it reaches will be 20 m.

We know the equation

u = gt

substitute u = 20, g = 10

20 = 10 × t

t = 20/10

t = 2 seconds

Therefore, the time taken by it to reach the height will be: t = 2 seconds.

3 0
3 years ago
You are an astronomer on planet Nearth, which orbits a distant star. It has recently been accepted that Nearth is spherical in s
spayn [35]

You know now that 1200 km is 11° of latitude on the planet. So its circumference is roughly approximately around something like about

(360/11) • (1200 km) = 39,273 km

If it was good enough for Eratosthenes, then we can't complain.

4 0
3 years ago
Read 2 more answers
A child in a boat throws a 6-kg package horizontally to the right with a speed of 8 m/s.
victus00 [196]

Answer:

0.5 m/s

Explanation:

Using conservation of momentum, P1=P2, the system starts off with zero momentum as nothing is moving. But in the second part of the equation(P2) the child throws the package to the right. By Newton's third law, the child and the boat should move to the left. Plugging in what we know, 0= -90v + 6kg*8m/s. Solving for v you will get 0.5 meters per second. The mass is 90kg as that the is mass of the child and boat combined. I also made it negative as the boat and child move left (I designated this as the negative direction) and the package's momentum is positive as it is moving to the right.

4 0
3 years ago
The mantle in the earths core continuously heat up and cool down using convection currents
o-na [289]
This statements is true
7 0
3 years ago
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