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Evgesh-ka [11]
3 years ago
5

I need help with this asap.​

Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

H30+ First H20 Second N03 Third HNO3 Fourth

Explanation:

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How many milliliters of 0.500 m kcl solution would you need to dilute to make 100.0 ml of 0.100 m kcl?
Strike441 [17]
Given:
 Concentration 1 = 100.0 ml              Concentration 2 = ?
 Volume 1 = 0.100 M KCL                  Volume 2= 0.500 M KCL

Find Concentration 2

To get the concentration 2, follow this formula

C1V1 = C2V2

Solution

(100.0 ml) (0.100 m kcl) = (X ml) (0.500 m kcl)
 transfer the volume 2 to the left side

(100.0 ml) (0.100 m kcl) = X ml
---------------------------------
            0.500 m kcl

10.00ml / m kcl = Xml
--------------------                   cancel the m kcl to let the ml be the remaining variable
0.500 m kcl

20.0 ml = x ml

So you will need 20.0 ml of 0.500 m kcl to made the solution of 100.0 ml of 0.100 m kcl 
8 0
3 years ago
I need your help please with this question!!
castortr0y [4]

Hey there!

The first one:

The 20 means it has 20 protons. The 42 means the sum of protons and neutrons is 42, so that means 20 protons plus 22 neutrons is 42 total. There is no charge noted, so the number of electrons is equal to the number of protons.

This atom has 20 protons, 22 neutrons, and 20 electrons.

The second one:

The 20 means it has 20 protons. The 44 means the sum of protons and neutrons is 44, so that means 20 protons plus 24 neutrons is 44 total. There is no charge noted, so the number of electrons is equal to the number of protons.

This atom has 20 protons, 24 neutrons, and 20 electrons.

Hope this helps!

6 0
3 years ago
Name an element in the third period (row) of the periodic table with one valence electron.
Salsk061 [2.6K]
Sodium (Na)

Founder is Humphry Davy

Discovery year is 1807
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likoan [24]
I would sat the answer will be condensation if that's one of your choices
4 0
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Vinil7 [7]
The reaction is a hydrogenation reaction of an alkene, and its equation is:
C₂H₄(g) + H₂(g) → C₂H₆(g)
Therefore, this reaction can be sped up just as any other irreversible reaction may have its rate increased, by increasing temperature and pressure to increase the effective collisions of molecules.
5 0
3 years ago
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