Answer:
The value of the acceleration of gravity of the Unknown Planet = 1.14 
Explanation:
length of the pendulum (L)= 1.15 m
Time period (T)= 6.29 seconds
We know that time period  of a simple pendulum is given by
⇒ T = 2 ×
 ×  
 
put the values in the above formula we get 
⇒ T = 2 ×
 × 
⇒ 6.29 = 2 ×
 × 
By solving the above equation we get 
⇒ g = 1.14 
This is the value of the acceleration of gravity of the Unknown Planet.
 
        
             
        
        
        
It’s called the focus of the earthquake
        
             
        
        
        
Answer:

Explanation:
mass of proton, m = 1.67 x 10^-27 kg 
speed of proton, v = 350 km/s = 350,000 m/s
Momentum of proton, p = mass x speed 
p =  1.67 x 10^-27 x 350000 = 5.845 x 10^-22 kg m /s 
uncertainty in momentum, Δp = 0.1 % of p 
Δp = 
According to the principle

where, Δx be the uncertainty in position


 
        
             
        
        
        
Answer:
A) F = 1.8375 N, B) V = 1.25 10⁻⁴ m³, C) V= 1.25 10⁻⁴ m³
Explanation:
This exercise should select some values such as the weight of the block m=0.250 kg and the density of the liquid ρ = 500 kg / m³ (water); with these values answer the question, for this we use the static equilibrium relations.
           Σ F = 0
           F + B - W = 0
the expression for thrust is
           B = ρ g V_liquid
A) the weight of the block is
           W = m g
           W = 0.250 9.8
           W = 2.45 N
Let's look for the maximum push
            V_body = V_liquid
             B = 500 9.8 0.05³
            B = 0.6125 N
we substitute
           F = W - B
           F = 2.45 - 0.6125
           F = 1.8375 N
B) As the body is totally submerged, the volume of the liquid and the body are equal
            V = l³
            V = 0.05³
            V = 1.25 10⁻⁴ m³
C) the volume of water displaced is equal to the volume of the body
            V_liquid = 1.25 10⁻⁴ m³