Answer:
0,31%
Explanation:
For the reaction:
I₂ + 2 S₂O₃²⁻ → 2 I⁻ + S₄O₆²⁻
0,043 L × 0,117 M of sodium tiosulfate = 5,031x10⁻³ moles of S₂O₃²⁻
5,031x10⁻³ moles of S₂O₃²⁻ ×
= <em>2,5156x10⁻³ moles of I₂</em>
These moles of I₂ were produced from:
ClO⁻⁻ + 2 H⁺ + 2 I⁻ → I₂ + Cl⁻ + H2O
2,5156x10⁻³ moles of I₂ ≡ moles of NaClO
2,5156x10⁻³ moles of NaClO ×
=<em> 0,187 g of NaClO</em>
Thus, percentage composition by mass is:
=<em> 0,31%</em>
I hope it helps!
Answer:
The pOH of a solution is the negative logarithm of the hydroxide-ion concentration. The pH of a solution can be related to the pOH.
I looked it up, so idk if it is right...
Answer:
You can see in the above illustration of the periodic table that N is in Period 4, Group 5A, and p-block. Before reaching N, you will pass through the atomic orbitals 1s, 2s, and 2p. The electron configuration of N3- is N3-: 1s22s22p6 .
Explanation:
1s^2 2s^2 2p^<span>2 is the electronic configuration for carbon I think</span>