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schepotkina [342]
3 years ago
9

Describe what happens to the KE of the simple pendulum as it swings back and forth.

Physics
2 answers:
diamong [38]3 years ago
8 0

Answer:

Explanation: do y like me yes or no

Sauron [17]3 years ago
4 0
As the pendulum swings back and forth, the balance between the two types of energy changes constantly. At some points in its swing, the pendulum has more kinetic energy. At other points, it has more potential energy. Of course, no working system is ideal. pendulum is an object hung from a fixed point that swings back and forth under the action of gravity. ... When the swing is raised and released, it will move freely back and forth due to the force of gravity on it. As a pendulum swings, its potential energy converts to kinetic and back to potential. Recall the concept of conservation of energy—that energy may change its form, but have no net change to the amount of energy.
Answer. Answer: When you let go of the raised bob, its potential energy is converted to kinetic energy as it swings down with increasing speed, and then back to potential energy as it swings up on the other side with decreasing speed. The massive object is affectionately referred to as the pendulum bob. When the bob is displaced from equilibrium and then released, it begins its back and forth vibration about its fixed equilibrium position. The motion is regular and repeating, an example of periodic motion.
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The pressure of the air at the way its blowing

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3 years ago
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Andru [333]

Answer:

Two positively charged particles

Explanation:

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3 years ago
A mango falls fromthe top its tree passing a window which is 2.4m tall by taking 0.4s
Natasha2012 [34]

Explanation:

There are three points in time we need to consider.  At point 0, the mango begins to fall from the tree.  At point 1, the mango reaches the top of the window.  At point 2, the mango reaches the bottom of the window.

We are given the following information:

y₁ = 3 m

y₂ = 3 m − 2.4 m = 0.6 m

t₂ − t₁ = 0.4 s

a = -9.8 m/s²

t₀ = 0 s

v₀ = 0 m/s

We need to find y₀.

Use a constant acceleration equation:

y = y₀ + v₀ t + ½ at²

Evaluated at point 1:

3 = y₀ + (0) t₁ + ½ (-9.8) t₁²

3 = y₀ − 4.9 t₁²

Evaluated at point 2:

0.6 = y₀ + (0) t₂ + ½ (-9.8) t₂²

0.6 = y₀ − 4.9 t₂²

Solve for y₀ in the first equation and substitute into the second:

y₀ = 3 + 4.9 t₁²

0.6 = (3 + 4.9 t₁²) − 4.9 t₂²

0 = 2.4 + 4.9 (t₁² − t₂²)

We know t₂ = t₁ + 0.4:

0 = 2.4 + 4.9 (t₁² − (t₁ + 0.4)²)

0 = 2.4 + 4.9 (t₁² − (t₁² + 0.8 t₁ + 0.16))

0 = 2.4 + 4.9 (t₁² − t₁² − 0.8 t₁ − 0.16)

0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)

0 = 2.4 − 3.92 t₁ − 0.784

0 = 1.616 − 3.92 t₁

t₁ = 0.412

Now we can plug this into the original equation and find y₀:

3 = y₀ − 4.9 t₁²

3 = y₀ − 4.9 (0.412)²

3 = y₀ − 0.83

y₀ = 3.83

Rounded to two significant figures, the height of the tree is 3.8 meters.

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Atoms of which pair of elements will form covalent bonds in a compound? ASAP PLZ
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Answer:

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