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3 years ago

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Physics

1 answer:

Semmy [17]3 years ago

8 0

Answer:

19,224 N

Explanation:

The given parameters are;

The mass limit of the elevator = 2,400 kg

The maximum ascent speed = 18.0 m/s

The maximum descent speed = 10.0 m/s

The maximum acceleration = 1.80 m/s²

Given that the acceleration due to gravity, g ≈ 9.81 m/s²

The minimum upward force that the elevator cable exert on the elevator car, $F_{min}$ , is given in the downward motion as follows;

$F_{min}$ = m·g - m·a

∴ $F_{min}$ = 2,400 kg × 9.81 m/s² - 2,400 kg × 1.80 m/s² = 19,224 N

The minimum upward force that the elevator cable exert on the elevator car, $F_{min}$ = 19,224 N

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A) is repelled by the sphere

Explanation:

When a piece of plastic is rubbed with a wooden cloth, it sinks negatively
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3 years ago

Two resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are

Contact [7]

Answer:

r=0.127

Explanation:

When connected in series

Current = I

When connected in parallel

Current = 10 I

We know that equivalent resistance

In series R = R₁+R₂

in parallel R= R₁R₂/(R₂+ R₁)

Given that voltage is constant (Vo)

V = I R

Vo = I (R₁+R₂) ------------1

Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2

From above equations

10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)

10 R₁R₂ = (R₁+R₂) (R₂+ R₁)

10 R₁R₂ = 2 R₁R₂ + R₁² + R₂²

8 R₁R₂ = R₁² + R₂²

Given that

r = R₁/R₂

Divides by R₂²

8R₁/R₂ = ( R₁/R₂)²+ 1

8 r = r ² + 1

r ² - 8 r+ 1 =0

r= 0.127 and r= 7.87

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8 0

4 years ago

A doorframe is twice as tall as it is wide. There is a positive charge on the top left corner and an equal but negative charge i

Andrei [34K]

Answer:

α = 141.5° (counterclockwise)

Explanation:

q₁ = +q

q₂ = -q

q₃ < 0

b = 2*a

We apply Coulomb's Law as follows

F₁₃ = K*q₁*q₃ / d₁₃² = + K*q*q₃ / (2*a)² = + K*q*q₃ / (4*a²)

F₂₃ = K*q₂*q₃ / d₂₃² = - K*q*q₃ / (5*a²)

(d₂₃² = a² + (2a)² = 5*a²)

Then

∅ = tan⁻¹(2a/a) = tan⁻¹(2) = 63.435°

we apply

F₃x = - F₂₃*Cos ∅ = - (K*q*q₃ / (5*a²))* Cos 63.435°

⇒ F₃x = - 0.0894*K*q*q₃ / a²

F₃y = - F₂₃*Sin ∅ + F₁₃

⇒ F₃y = - (K*q*q₃ / (5*a²))* Sin 63.435° + (K*q*q₃ / (4*a²))

⇒ F₃y = 0.0711*K*q*q₃ / a²

Now, we use the formula

α = tan⁻¹(F₃y / F₃x)

⇒ α = tan⁻¹((0.0711*K*q*q₃ / a²) / (- 0.0894*K*q*q₃ / a²)) = - 38.5°

The real angle is

α = 180° - 38.5° = 141.5° (counterclockwise)

4 0

4 years ago