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3 years ago

The atomic number of an element indicates the number of?

Chemistry

1 answer:

marshall27 [118]3 years ago

6 0

Answer:

The number is mostly related to the mass or the weight of the element.

Explanation:

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In this experiment, student groups ran repeated trials (5) and then averaged their data. ALL BUT ONE statement explains why

Colt1911 [192]

Answer:

its B

Explanation:

trust me i had this in my usatestprep, also follow me on tiktok, its ultrasolos

3 0

3 years ago

Read 2 more answers

An alloy with an average grain diameter of 35 μm has a yield strength of 163 Mpa, and when it undergoes strain hardening, the gr

Lera25 [3.4K]

Answer:

$\sigma_y\ =210.2\ MPa$

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

$\sigma_y=\sigma_o+\dfrac{K}{\sqrt d}$

$\sigma_y\ =Yield\ strength$

d = diameter

K =Constant

$\sigma_o\ =material\ constant$

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

$163=\sigma_o+\dfrac{K}{\sqrt 35}$ ------------1

d= 17 μm ,yield strength = 192 MPa

$192=\sigma_o+\dfrac{K}{\sqrt 17}$ ------------2

From equation 1 and 2

$192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}$

K=394.53

By putting the values of K in equation 1

$163=\sigma_o+\dfrac{394.53}{\sqrt 35}$

$\sigma_o\ =96.31\ MPa$

$\sigma_y=96.31+\dfrac{394.53}{\sqrt d}$

Now when d= 12 μm

$\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}$

$\sigma_y\ =210.2\ MPa$

4 0

3 years ago

Calculate the amount of C in 0.600g of CO2.

pashok25 [27]

Answer: Since one molecule of CO2 contains one molecule carbon atoms, therefore, 0.6 molecule of carbon dioxide will contain 0.6 molecule of carbon.

Mass of C in 0.6 molecule of CO2

Explanation

= No. Of molecule × molar mass

= 0.6× 12gm

=7.2gm

8 0

3 years ago

Thermal energy always moves from where there is ____of it to where there is ____of it until ____.

DENIUS [597]

Answer:

Thermal energy always moves from where there is more of it to where there is less of it until distributed.

Explanation:

Its true, just don't know if its correct for your assignment

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3 years ago

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A radioactive isotope of potassium (k) has a half-life of 20 minutes. if a 43 gram sample of this isotope is allowed to decay fo

Ksenya-84 [330]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 43 g

m (final mass after time T) = ? (in g)

x (number of periods elapsed) = ?

P (Half-life) = 20 minutes

T (Elapsed time for sample reduction) = 80 minutes

Let's find the number of periods elapsed (x), let us see:

$T = x*P$

$80 = x*20$

$80 = 20\:x$

$20\:x = 80$

$x = \dfrac{80}{20}$

$\boxed{x = 4}$

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

$m = \dfrac{m_o}{2^x}$

$m = \dfrac{43}{2^{4}}$

$m = \dfrac{43}{16}$

$\boxed{\boxed{m = 2.6875\:g}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

8 0

4 years ago